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How high up is a 3 kg object that has 300 J of energy?
The height of the 3 kg object can be determined using the formula for gravitational potential energy: Potential energy = mass x gravity x height. Given that the potential energy is 300 J and the mass is 3 kg, the height can be calculated by rearranging the formula as: Height = potential energy / (mass x gravity). Assuming gravity is approximately 9.81 m/s^2, the object would be approximately 9.71 meters high.
How high up is a 3 kg objectthat has 300 joules of energy?
The height can be calculated using the potential energy formula PE = mgh, where m is the mass (3 kg), g is the acceleration due to gravity (~9.8 m/s^2), and h is the height. Rearranging the formula, h = PE / (mg). Plugging in the values, h = 300 J / (3 kg * 9.8 m/s^2) ≈ 10 meters.
How fast will an object be moving if its kinetic energy is 300 joules and has a mass of 0.05 kilograms?
To calculate the speed of the object, you can use the formula for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the object, and v is the speed. Rearrange the formula to solve for v: v = sqrt(2 * KE / m). Plugging in the values given (KE = 300 J and m = 0.05 kg) will give you the speed of the object.
What is the potential energy of a 10.2 kg rock that is sitting on top of a hill that is 300 meters high?
The potential energy of the rock can be calculated using the formula: potential energy = mass × gravity × height. Given the mass of the rock (10.2 kg), the height of the hill (300 meters), and the acceleration due to gravity (approximately 9.81 m/s^2), the potential energy would be 10.2 kg × 9.81 m/s^2 × 300 m = 29970.6 Joules.
Using Einstein's formula if an object has a mass of 300kg what is its energy?
To find the energy of an object using Einstein's formula (E=mc^2), first convert mass from kg to kg (1 kg = 1000 g) and light speed (c) is 3x10^8 m/s. Then, substitute the values into the formula E=mc^2 to calculate the energy. The energy of an object with a mass of 300 kg would be E = 300 kg x (3 x 10^8 m/s)^2.
How high up is a 3 kg object that has 300 J of energy?
The height of the 3 kg object can be determined using the formula for gravitational potential energy: Potential energy = mass x gravity x height. Given that the potential energy is 300 J and the mass is 3 kg, the height can be calculated by rearranging the formula as: Height = potential energy / (mass x gravity). Assuming gravity is approximately 9.81 m/s^2, the object would be approximately 9.71 meters high.
How much force is applied to an object if 300 j of work is done on it over a distance of 50 m?
W=FxD (work equals force times distance) 300j = F (50m) 300/50= 6 N OK, that assumes a constant force over the whole distance. N = Newtons (force)
How high up is a 3 kg objectthat has 300 joules of energy?
The height can be calculated using the potential energy formula PE = mgh, where m is the mass (3 kg), g is the acceleration due to gravity (~9.8 m/s^2), and h is the height. Rearranging the formula, h = PE / (mg). Plugging in the values, h = 300 J / (3 kg * 9.8 m/s^2) ≈ 10 meters.
How fast will an object be moving if its kinetic energy is 300 joules and has a mass of 0.05 kilograms?
To calculate the speed of the object, you can use the formula for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the object, and v is the speed. Rearrange the formula to solve for v: v = sqrt(2 * KE / m). Plugging in the values given (KE = 300 J and m = 0.05 kg) will give you the speed of the object.
How much work is being done if a 100 n box is lifted meters of the ground?
Work = force x displacementW = Fd W = 100N x 3m W = 300J 300 joules of work is done on the box.
What is 300 decreased by 25 percent?
300 - 25% = 300 x (1 - (25/100)) = 300 x 0.75 = 225
Decrease 300 by25%?
[object Object]
is 300 too high?
is 300 too high?
What is the density of an object have a mass of 54 and a volume of 300?
The density of the object is 0.18 g/cm^3, calculated by dividing the mass of 54g by the volume of 300 cm^3.
What number is364 588 less than 300 000?
-64,588
What is the potential energy of a 10.2 kg rock that is sitting on top of a hill that is 300 meters high?
The potential energy of the rock can be calculated using the formula: potential energy = mass × gravity × height. Given the mass of the rock (10.2 kg), the height of the hill (300 meters), and the acceleration due to gravity (approximately 9.81 m/s^2), the potential energy would be 10.2 kg × 9.81 m/s^2 × 300 m = 29970.6 Joules.
Using Einstein's formula if an object has a mass of 300kg what is its energy?
To find the energy of an object using Einstein's formula (E=mc^2), first convert mass from kg to kg (1 kg = 1000 g) and light speed (c) is 3x10^8 m/s. Then, substitute the values into the formula E=mc^2 to calculate the energy. The energy of an object with a mass of 300 kg would be E = 300 kg x (3 x 10^8 m/s)^2.
