How far will a freely falling object fall from rest in five seconds?

Answer 1

I think it would depend on how much the object weighed, wouldn't it? Like Bowling ball vs. wiffle ball?

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The above answer is incorrect. The object falls about 125 meters or roughly 410 feet if it has little or no air resistance.

More detail is available below.

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The following equation assumes there is no air resistance, but that can severely affect results. A penny of the same weight as a feather clearly falls faster, as the feather has more cross-sectional area.

Like the above example for instance: a wiffle ball's rough and uneven surface has more air resistance than the bowling ball's slick surface, so it doesn't accelerate as quickly and also reaches its terminal velocity more quickly.

It also assumes that the object has no initial speed. A ball thrown downwards clearly would go farther than one that was dropped.

The equation is

d=(1/2)(a)(t2)

where [d] is distance, [a] is acceleration (acceleration due to gravity is considered to be roughly 9.8 meters per seconds squared or 10 m/s), and [t] is the time.

If we plug and chug...

d=(1/2)(10)(52)

d=(5)(25)

d=125

That's 125 meters, or roughly 410 feet.

Answer 2

A freely falling object will fall approximately 122.5 meters from rest in five seconds under the influence of gravity. This value is based on the acceleration due to gravity, which is approximately 9.81 m/s^2.

Answer 3

15 meters

We can use the equation v2 = v02+2ax to find out how fast the object is moving after the first interval of time (a = 9.8 m/s2, which is acceleration due to gravity):

v2 = 0 + 2(9.8)(5)

v2 = 98

v = √98

v = 9.8995 (approx.)

We can then use the equation v = v0+at to find the time it took to fall 5 meters (and therefore the length of an interval):

√98 = 0 + (9.8)t

t = (√98)/9.8

t = 1.0102 (approx.)

Finally we can use the equation x = v0t+(1/2)at2 to calculate how far it fell during the second (√98)/9.8 seconds.

x = (9.8955)(1.0102) + (1/2)(9.8)(1.0102)2

x = 15.00 meters

Answer 4

this depends on the mass and weight of said object.

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500 years of human inquiry and achievement down the drain !

It has nothing to do with the mass or weight of said object.

If they are truly "free falling", then a feather and a battleship will accelerate at the

same rate, and will have the same speed after 5 seconds.

If this drama is unfolding on or near the Earth, then that speed will be 49 meters

(160.8 feet) per second.

Since it started out being dropped with zero speed, its average speed during that

time is 24.5 meters per second, and the distance it falls during the first 5 seconds

after being dropped is (24.5 x 5) = 122.5 meters (401.9 feet).

Answer 5

On or near earth, the acceleration of gravity is 9.8 meters (32.2 feet) per second2 .

After 5 seconds of fall without air resistance, the speed of fall is

49 meters (160.8 feet) per second.

Answer 6

In order to answer this question it is necessary to assume that

• the stone was at rest before it started falling;
• it is falling under the force of the earth's gravity and no other force (it was not thrown);
• air resistance can be ignored.

In that case, it will fall approx 44 metres.

Answer 7

Please use the formula:v = v0 + at

Where v0 is the initial velocity, a is the acceleration, and t is the time. The acceleration near Earth is approximately 9.8 meters per square second.

Answer 8

D=1/2AT square

5m/s * 5 square

125M

Answer 9

depends on size and weight

Answer 10

122.5 meters (402.5 feet)