How far will a falling object move in 9 seconds?

Answer 1

s=ut+1/2 at^2

so if your u=0

s=1/2*a*t^2=1/2*9.8*9*9=396.9m

Answer 2

We can find the velocity after 8 seconds using the equation v = v0 + at, so

v = 0 + (9.8)(8), v = 78.4. We can then use the equation v2 = v02 + 2ax to find how far it will fall:

78.42 = 02 + 2(9.8)x

x = 78.42/(2*9.8) = 313.6

The object will fall about 313.6 meters.

(Your final answer may differ a little due to rounding differences.)

Answer 3

In the first six inches a falling object travels six inches.

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Another contributor added some background:

According to most of the evidence that has been collected in physical and mechanical

mensuration laboratories throughout most of the twentieth Century, a definite pattern

has begun to emerge. We can now say with some assurance that to the limits of the

most modern techniques of observation, if Newton's Laws are accurate and the

relativistic contractions and dilatations are small enough to be ignored, then we can

even include the effects of air resistance ... an encouraging confirmation of the underlying

theory ... and state with a high degree of confidence that the answer to the question is:

Precisely six inches.

Answer 4

The distance a falling object moves in 9 seconds depends on the acceleration due to gravity (approximately 9.81 m/s^2). Using the equation of motion for free fall (s = 0.5 * g * t^2), the object will fall approximately 397.1 meters in 9 seconds.

Answer 5

s=?

u=0

t=6

a=9.8

s=ut+1/2at^2

s-1/2*(4.9)*6^2

Falls 88.2 meters