Air resistance can affect the measurement of the acceleration due to gravity (g) by slowing down the fall of a free-falling object. This can result in a lower acceleration value than the actual value. To minimize the impact of air resistance, experiments are often conducted in a vacuum to ensure more accurate measurements of g.
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If air resistance is negligible, the object will return to its original position with the same speed as it had initially. However, if air resistance is appreciable, the object will return with a lower speed than initially due to the air resistance acting against its motion, causing energy loss.
The factors that affect the amount of air resistance from the force of gravity are the object's speed (faster speed leads to higher air resistance), the object's surface area (larger surface area leads to higher air resistance), and the density of the air through which the object is moving (higher air density leads to higher air resistance).
When the object reaches terminal velocity, the force of air resistance is equal in magnitude to the force of gravity acting on the object. At this point, the net force on the object is zero, so the force of air resistance is equal to the weight of the object (mg), where m is the mass of the object and g is the acceleration due to gravity (9.81 m/s^2). Therefore, the force of air resistance in this case would be 2 kg * 9.81 m/s^2 = 19.62 N.
No, in a vacuum or free-fall scenario, the acceleration due to gravity (g) is the maximum downward acceleration an object can experience. Any object falling under gravity without air resistance will have an acceleration equal to g (approximately 9.81 m/s^2).
Yes. Every body that is falling, (if there is no other force then the gravity force) will fall in constant acceleration. Mass does not affect the acceleration of the body. According to Newton's second law: F=m*a m*g=m*a g=a F= Force m= mass a= acceleration g= gravity acceleration m*g= the force of gravity