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I assume you are asking this in regards to an inclined plane so I will answer it accordingly,
Well Recall the equation
Force = Mass x Acceleration.
In the case of free falling objects Acceleration is equal to gravity, however, on an inclined plan the presence of an incline prevents the object from falling straight down. Instead it must accelerate with some component of gravity.
Now recall that perpendicular forces of action on an Incline plane are calculated by Sin theta and that perpendicular forces ( the normal force) is calculated by Cos theta
Hence because the object is accelerating down an incline the formula for its total force parallel to the object would be
Force = mg sin theta
Now if you remember, if you simply remove the mass from the above equation you will be left with the acceleration component of the problem ala the force = mass x acceleration formula.
So gsintheta represents A ( acceleration) in the Force = mass times acceleration formula.
What else can I help you with?
What is the relationship between g and acceleration of a pendulum?
The acceleration of a pendulum is directly proportional to the acceleration due to gravity (g). The formula to calculate the acceleration of a pendulum is a = g * sin(theta), where theta is the angle between the pendulum and the vertical line. This means that an increase in g will result in a corresponding increase in the acceleration of the pendulum.
Acceleration related to angle of inclination?
The acceleration of an object on an incline is influenced by the angle of inclination. A steeper incline will result in a greater component of the object's weight acting parallel to the incline, leading to a greater acceleration. The acceleration can be calculated using the formula a = g * sin(theta), where "a" is the acceleration, "g" is the acceleration due to gravity, and "theta" is the angle of inclination.
What is the eq of constant for a sphere rolling in a frictional less incline surface?
The equation for the constant acceleration of a sphere rolling without slipping on a frictionless inclined plane is given by a = g * sin(theta) / (1 + (I / (m * r^2))), where a is the acceleration, g is the acceleration due to gravity, theta is the angle of the incline, I is the moment of inertia of the sphere, m is the mass of the sphere, and r is the radius of the sphere.
How to calculate the acceleration in terms of g's for an object in free fall?
To calculate the acceleration in terms of g's for an object in free fall, divide the acceleration due to gravity (9.8 m/s2) by the acceleration of the object. This will give you the acceleration in terms of g's, where 1 g is equal to the acceleration due to gravity.
What is the equation for normal force?
The equation for normal force is: ( F_{\text{N}} = \text{mg} \cos(\theta) ), where ( F_{\text{N}} ) is the normal force, ( m ) is the mass of the object, ( g ) is the acceleration due to gravity, and ( \theta ) is the angle of incline.
Use of an inclined plane in physics Hey guys I'm doing a prac investigation on an inlcined plane. I was wondering does mass affect acceleration down the incline?
inclined planes can be used in the investigation of acceleration. specificaly using m*g*sin(theta)=a (well i think that was the equation) acceleration is equal to mass*gravity*sin(theta) where sin(theta) is equal to opposite(o) over hypotenuse(h) or theta = (1/sin) * o/h
What is the relationship between g and acceleration of a pendulum?
The acceleration of a pendulum is directly proportional to the acceleration due to gravity (g). The formula to calculate the acceleration of a pendulum is a = g * sin(theta), where theta is the angle between the pendulum and the vertical line. This means that an increase in g will result in a corresponding increase in the acceleration of the pendulum.
Acceleration related to angle of inclination?
The acceleration of an object on an incline is influenced by the angle of inclination. A steeper incline will result in a greater component of the object's weight acting parallel to the incline, leading to a greater acceleration. The acceleration can be calculated using the formula a = g * sin(theta), where "a" is the acceleration, "g" is the acceleration due to gravity, and "theta" is the angle of inclination.
What is the eq of constant for a sphere rolling in a frictional less incline surface?
The equation for the constant acceleration of a sphere rolling without slipping on a frictionless inclined plane is given by a = g * sin(theta) / (1 + (I / (m * r^2))), where a is the acceleration, g is the acceleration due to gravity, theta is the angle of the incline, I is the moment of inertia of the sphere, m is the mass of the sphere, and r is the radius of the sphere.
Why does the acceleration of an object rolled down an incline increase as the angle of incline increases?
The contribution of the acceleration of gravity in the direction of motion increases as the angle of the incline increases. Or in other words, as the angle between the direction of motion and the force of gravity goes to zero, the acceleration of the object goes to the gravitational acceleration. a = g cos(theta) Where theta is the angle between the direction of motion and verticle, which is in fact (theta = 90 - angle of the incline)Where a is the acceleration of the object down the incline plane and g is the acceleration due to gravity. Theta is the angle between the direction of motion of the accelerating object and the acceleration of gravity. Initially, the angle between a and g is 90 degrees (no incline) and therefore g contributes nothing to the objects acceleration. a = g cos(90) = 0 As the angle of the inclined is increased, the angle between a and g approaches zero, at which point a = g. With no other forces acting upon the object, g is its maximum acceleration.
What is the speed and acceleration of a ball rolling down a hill?
The acceleration of a tennis ball rolling down an incline depends with two factors. The force that is applied to the tennis ball and the mass of the tennis ball will determine its acceleration.
A solid homogenous sphere rolls without slipping down a plane that makes an angle of 30 degree with the horizontal find the linear acceleration of the sphere and the minimum coefficient of friction?
The linear acceleration of the sphere down the incline can be calculated using the formula (a = g \sin(\theta)), where (g) is the acceleration due to gravity (9.8 m/s(^2)) and (\theta) is the angle of the incline. Substituting the values, we get (a = 9.8 \times \sin(30) = 4.9 , \text{m/s}^2). The minimum coefficient of friction required to prevent slipping can be calculated using the formula (\mu_{\text{min}} = \tan(\theta)), where (\mu_{\text{min}}) is the minimum coefficient of static friction. Substituting the values, we get (\mu_{\text{min}} = \tan(30) \approx 0.577).
It is observed that all bodies sliding down a frictionless inclined plane have the same acceleration how does its happen?
Fx=G*sin(t) = m*g*sin(t) a=Fx/m=g*sin(t) ->> does not depend on mass
How to calculate the acceleration in terms of g's for an object in free fall?
To calculate the acceleration in terms of g's for an object in free fall, divide the acceleration due to gravity (9.8 m/s2) by the acceleration of the object. This will give you the acceleration in terms of g's, where 1 g is equal to the acceleration due to gravity.
What is the equation for normal force?
The equation for normal force is: ( F_{\text{N}} = \text{mg} \cos(\theta) ), where ( F_{\text{N}} ) is the normal force, ( m ) is the mass of the object, ( g ) is the acceleration due to gravity, and ( \theta ) is the angle of incline.
What is the acceleration of a block on an inclined plane?
The acceleration of a block on an inclined plane is determined by the angle of the incline and the force of gravity acting on the block. It can be calculated using the formula: acceleration (sin ) g, where is the angle of the incline and g is the acceleration due to gravity (approximately 9.81 m/s2).
What will be the range if theta45 degrees and height is given in projectile motion?
it will only be four times the height.simply use kinematics to find the relationship between height,initial speed and angle of projection theta, ull get( u^2 sin^2theta)/2g, g of course being the acceleration due to gravity, wheras range will turn out to be (u^2 sin2(theta))/g..thump in the values..very easy to see that range is 4 times the height..cheers
