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To calculate the extension of a spring with mass attached to it, you can use Hooke's Law, which states that the force exerted by the spring is directly proportional to the extension of the spring. The formula is F = kx, where F is the force applied, k is the spring constant, and x is the extension of the spring. By rearranging the formula, you can calculate the extension x = F / k.
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What is the relationship between extension and mass?
The relationship between extension and mass is described by Hooke's Law, which states that the extension of a spring is directly proportional to the force applied to it, as long as the elastic limit of the material is not exceeded. This means that the greater the mass attached to the spring, the more it will stretch. The relationship can be expressed mathematically as F = kx, where F is the force applied, k is the spring constant, and x is the extension of the spring.
A frequency of vibration of a mass-spring system is 5Hz when a 4g mass is attached to the spring .Calculate the forces constant of the spring?
To calculate the force constant of the spring (k), you can use the formula for the frequency of vibration of a mass-spring system: f = 1 / (2π) * √(k / m) where f is the frequency, k is the force constant of the spring, and m is the mass. Rearranging the formula gives: k = (4π^2 * m * f^2). Plugging in the given values: k = (4π^2 * 0.004 * 5^2) ≈ 1.256 N/m.
What is the effective mass of spring?
The effective mass of a spring is the mass that would behave the same way as the spring when subjected to a force or acceleration. It is a concept used in physics to simplify calculations in systems involving springs. The effective mass of a spring depends on its stiffness and the mass it is attached to.
Why the mass of the spring had not necessarily been taken into consideration in the spring elastisity experiment?
In the spring elasticity experiment, the mass of the spring is often neglected because the mass of the spring itself is usually negligible compared to the masses being hung on it. Additionally, the focus of the experiment is typically on the relationship between the force applied to the spring and the resulting extension, rather than the mass of the spring.
Is the period of a vibrating spring linearly affected by the mass of the attached object?
No, the period of a vibrating spring is not linearly affected by the mass of the attached object. In fact, the period is directly proportional to the square root of the mass. This means that as the mass of the object increases, the period will increase, but not in a linear fashion.
Predict how many centimeters the spring will stretch if a total mass of 700 grams were attached?
To predict how many centimeters the spring will stretch, we need to know the spring constant in N/cm and apply Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to its extension. By knowing the spring constant and the total mass attached, we can calculate the stretch.
What is the relationship between extension and mass?
The relationship between extension and mass is described by Hooke's Law, which states that the extension of a spring is directly proportional to the force applied to it, as long as the elastic limit of the material is not exceeded. This means that the greater the mass attached to the spring, the more it will stretch. The relationship can be expressed mathematically as F = kx, where F is the force applied, k is the spring constant, and x is the extension of the spring.
Which states the relationship between the mass attached to the end of the spring and the length the spring is stretched?
more mass the longer the spring
A frequency of vibration of a mass-spring system is 5Hz when a 4g mass is attached to the spring .Calculate the forces constant of the spring?
To calculate the force constant of the spring (k), you can use the formula for the frequency of vibration of a mass-spring system: f = 1 / (2π) * √(k / m) where f is the frequency, k is the force constant of the spring, and m is the mass. Rearranging the formula gives: k = (4π^2 * m * f^2). Plugging in the given values: k = (4π^2 * 0.004 * 5^2) ≈ 1.256 N/m.
In a seismometer the pen is attached to an inertial mass suspended by a spring What is the rotating drum attached to?
the ground
What is the effective mass of spring?
The effective mass of a spring is the mass that would behave the same way as the spring when subjected to a force or acceleration. It is a concept used in physics to simplify calculations in systems involving springs. The effective mass of a spring depends on its stiffness and the mass it is attached to.
Why the mass of the spring had not necessarily been taken into consideration in the spring elastisity experiment?
In the spring elasticity experiment, the mass of the spring is often neglected because the mass of the spring itself is usually negligible compared to the masses being hung on it. Additionally, the focus of the experiment is typically on the relationship between the force applied to the spring and the resulting extension, rather than the mass of the spring.
How would k vary with different mass of trapped gas?
The value of the spring constant ''k'' in a spring-mass system would remain constant regardless of the mass of the trapped gas, as it only depends on the stiffness of the spring and not on the mass attached to it.
Is the period of a vibrating spring linearly affected by the mass of the attached object?
No, the period of a vibrating spring is not linearly affected by the mass of the attached object. In fact, the period is directly proportional to the square root of the mass. This means that as the mass of the object increases, the period will increase, but not in a linear fashion.
How do you calculate velocity of a box attached to a spring?
You can calculate the velocity of a box attached to a spring by using the equation v = ω * A * cos(ωt + φ), where v is the velocity of the box, ω is the angular frequency of the oscillation, A is the amplitude of the oscillation, t is the time, and φ is the phase angle. This equation is a result of the equations of motion for a simple harmonic oscillator like a spring-mass system.
A 75 kg mass attached to a vertical spring stretches the spring 30 m what is the spring constant?
24.5 newtons per meter
What are the variables that affect the period of an oscillating mass spring system?
The variables that affect the period of an oscillating mass-spring system are the mass of the object attached to the spring, the stiffness of the spring (its spring constant), and the damping in the system. The period is also influenced by the amplitude of the oscillations and the acceleration due to gravity.
