To calculate the extension of a spring with mass attached to it, you can use Hooke's Law, which states that the force exerted by the spring is directly proportional to the extension of the spring. The formula is F = kx, where F is the force applied, k is the spring constant, and x is the extension of the spring. By rearranging the formula, you can calculate the extension x = F / k.
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The relationship between extension and mass is described by Hooke's Law, which states that the extension of a spring is directly proportional to the force applied to it, as long as the elastic limit of the material is not exceeded. This means that the greater the mass attached to the spring, the more it will stretch. The relationship can be expressed mathematically as F = kx, where F is the force applied, k is the spring constant, and x is the extension of the spring.
The period of a spring is not affected by its mass. The period of a spring is determined by its stiffness and the force applied to it, not by the mass of the object attached to it.
To calculate the force constant of the spring (k), you can use the formula for the frequency of vibration of a mass-spring system: f = 1 / (2π) * √(k / m) where f is the frequency, k is the force constant of the spring, and m is the mass. Rearranging the formula gives: k = (4π^2 * m * f^2). Plugging in the given values: k = (4π^2 * 0.004 * 5^2) ≈ 1.256 N/m.
The period of a spring is influenced by factors such as the mass attached to the spring, the spring constant, and the amplitude of the oscillation.
The effective mass of a spring is the mass that would behave the same way as the spring when subjected to a force or acceleration. It is a concept used in physics to simplify calculations in systems involving springs. The effective mass of a spring depends on its stiffness and the mass it is attached to.