Wiki User
∙ 12y agoI presume you asking, "How can an atom of size about 1 angstrom absorb a photon whose wavelength is 5000 angstroms? Wouldn't the photon be too large for that atom?"
The paradox is resolved in this way: the instant you start to discuss electro-magnetic radiation as a photon instead of a transverse electro-magnetic wave, then you negate the wave-length aspect of the light. Instead, you view light as a collection of photons -- particles whose "size" (if that word has meaning) is point-like -- with a specific energy instead of specific wavelength.
A photon is NOT a snake-like wave, vibrating like a rubber band, with a length at least that of its wave-length, as it moves through a medium. A photon is a point particle with a specific energy.
You can describe light as a EM wave with a wave-length OR as a collection of point particles. You can NOT do both at the same time. Light exhibits the characteristics of one OR the other, but NEVER both.
Wiki User
∙ 12y agoAn atom can absorb a photon of 5000 wavelength through the process of photon absorption, where the energy of the photon is transferred to the atom, promoting an electron to a higher energy state within the atom. The size of the atom, in this case 1 angstrom, does not limit its ability to absorb the photon, as the interaction is determined by the energy of the photon and the energy levels of the atom.
The energy of a quantum of radiation is inversely proportional to its wavelength. The energy of a photon with a wavelength of 5000 Angstroms (500 nm) is approximately 2.48 electronvolts.
A sound wave with a frequency of 125 Hz has a wavelength of 40 meters (speed = frequency x wavelength). At a speed of 5000 m/s, this sound wave would have a period of 0.08 seconds (period = 1 / frequency).
The radio waves used by radio-controlled clocks and wristwatches operate at a frequency of 60 kHz, which corresponds to a wavelength of approximately 5000 meters. This wavelength allows the signal to penetrate buildings and obstacles, ensuring accurate time synchronization.
The period of a wave can be calculated using the equation Period = Wavelength / Wave Speed. Plugging in the values, we get Period = 10 mm / 50 m/s = 0.2 milliseconds.
The energy of a quantum of radiation can be calculated using the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength (5000 Å = 5000 x 10^-10 m). Substituting these values, the energy would be approximately 3.97 x 10^-19 Joules.
60Hz has a wavelength of 5000 meters.
The energy of a quantum of radiation is inversely proportional to its wavelength. The energy of a photon with a wavelength of 5000 Angstroms (500 nm) is approximately 2.48 electronvolts.
there is over 5000 speciesThey absorb water and you can release it by squeezing it
The absence of peaks in that range could indicate that the material being analyzed does not strongly absorb or emit light within that wavelength range. It could also suggest that the material has a smooth or continuous absorption or emission profile in that region.
A sound wave with a frequency of 125 Hz has a wavelength of 40 meters (speed = frequency x wavelength). At a speed of 5000 m/s, this sound wave would have a period of 0.08 seconds (period = 1 / frequency).
The radio waves used by radio-controlled clocks and wristwatches operate at a frequency of 60 kHz, which corresponds to a wavelength of approximately 5000 meters. This wavelength allows the signal to penetrate buildings and obstacles, ensuring accurate time synchronization.
A blackbody at a temperature of 10,000 K will emit most of its photons at what wavelength
The period of a wave can be calculated using the equation Period = Wavelength / Wave Speed. Plugging in the values, we get Period = 10 mm / 50 m/s = 0.2 milliseconds.
5000
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5000
The energy of a quantum of radiation can be calculated using the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength (5000 Å = 5000 x 10^-10 m). Substituting these values, the energy would be approximately 3.97 x 10^-19 Joules.