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To find the wavelength of a photon, you can use the equation c / f, where is the wavelength, c is the speed of light (approximately 3.00 x 108 m/s), and f is the frequency of the photon. Simply divide the speed of light by the frequency of the photon to calculate its wavelength.
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A photon has an energy of 1.94 1013 J What is the photon's wavelength?
To find the wavelength of the photon, you can use the formula: wavelength = (Planck's constant) / (photon energy). Substituting the values, the wavelength is approximately 1.024 x 10^-7 meters.
How does photon energy change with wavelength?
The energy of a photon is inversely proportional to its wavelength. This means that as the wavelength increases, the energy of the photon decreases. Conversely, as the wavelength decreases, the energy of the photon increases.
What is the wavelength of a photon whose energy is twice that of a photon with a 580 nm wavelength?
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
What occurs as the wavelength of a photon increases?
As the wavelength of a photon increases, its frequency decreases. This means the energy of the photon decreases as well, since photon energy is inversely proportional to its wavelength.
What is the wavelength of a photon with an energy of 3.38 10-19J?
The wavelength of a photon can be calculated using the equation E = hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 J s), and f is the frequency of the photon. From this, you can calculate the frequency of the photon using f = E/h. Then, you can use the speed of light equation c = fλ to find the wavelength with λ = c/f. Substituting the values accordingly, you can find the wavelength of the photon with 3.38 x 10^-19 J of energy.
A photon has an energy of 1.94 1013 J What is the photon's wavelength?
To find the wavelength of the photon, you can use the formula: wavelength = (Planck's constant) / (photon energy). Substituting the values, the wavelength is approximately 1.024 x 10^-7 meters.
What is the wavelength of the photon that has been released in Part B?
The wavelength of a photon can be calculated using the equation: wavelength = Planck's constant / photon energy. Given the photon energy, you can plug in the values to find the corresponding wavelength.
How does photon energy change with wavelength?
The energy of a photon is inversely proportional to its wavelength. This means that as the wavelength increases, the energy of the photon decreases. Conversely, as the wavelength decreases, the energy of the photon increases.
What is the wavelength of a photon whose energy is twice that of a photon with a 580 nm wavelength?
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
What occurs as the wavelength of a photon increases?
As the wavelength of a photon increases, its frequency decreases. This means the energy of the photon decreases as well, since photon energy is inversely proportional to its wavelength.
What is the wavelength of a photon with an energy of 3.38 10-19J?
The wavelength of a photon can be calculated using the equation E = hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 J s), and f is the frequency of the photon. From this, you can calculate the frequency of the photon using f = E/h. Then, you can use the speed of light equation c = fλ to find the wavelength with λ = c/f. Substituting the values accordingly, you can find the wavelength of the photon with 3.38 x 10^-19 J of energy.
A photon of wavelength 3000 A is absorbed by a gas and remitted as two photons One of the photons is red 7600 A What is the wavelength of the other photon?
The total energy of a photon with a wavelength of 3000 A is divided into two photons, one red photon with a wavelength of 7600 A, and another photon with a shorter wavelength. To calculate the wavelength of the second photon, you can use the conservation of energy principle, where the sum of the energies of the two new photons is equal to the energy of the original photon. This will give you the wavelength of the other photon.
How do you find the energy of a photon?
You need to know the photon's frequency or wavelength. If you know the wavelength, divide the speed of light by the photon's wavelength to find the frequency. Once you have the photon's frequency, multiply that by Planck's Konstant. The product is the photon's energy.
How can we calculate the wavelength of the photon emitted in a given scenario?
To calculate the wavelength of a photon emitted in a given scenario, you can use the formula: wavelength speed of light / frequency of the photon. The speed of light is approximately 3.00 x 108 meters per second. The frequency of the photon can be determined from the energy of the photon using the equation E hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10-34 joule seconds), and f is the frequency of the photon. Once you have the frequency, you can plug it into the formula to find the wavelength.
Does photon of 420nm contain more energy than a photon of 790nm?
Yes, a photon with a wavelength of 420nm contains more energy than a photon with a wavelength of 790nm. This is because energy is inversely proportional to wavelength, meaning shorter wavelengths have higher energy.
What is the frequency of a photon with wavelength 565nm?
The frequency of a photon can be calculated using the equation: frequency = speed of light / wavelength. Plugging in the values for speed of light and wavelength, the frequency of a photon with a wavelength of 565nm is approximately 5.31 x 10^14 Hz.
How do you calculate photon wavelength with only the energy of the photons?
Photon Energy E=hf = hc/w thus wavelength w= hc/E or the wavelength is hc divided by the energy of the photon or w= .2 e-24 Joule meter/Photon Energy.
