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Speed of electron as compared to speed of light is: n = 15% c = 299792458 [m/s]
v = c*n/100 = 4.5 *10^7 [m/s]
So corresponding wavelength as given by the de Broglie equation: h - Planck's constant, m0 - the mass of the electron at zero velocity;
lambda = h/p = h/(v*m0) = 6.62606876*10^-34/(4.5 *10^7*9.10938188*10^-31) = 1.61642*10^-11 [m] = 0.16 [angstroms]
To determine the wavelength of an electron with a velocity of 15.0 times the speed of light, you can use the de Broglie wavelength formula: λ = h / (m*v), where λ is the wavelength, h is the Planck constant, m is the mass of the electron, and v is the velocity. Plugging in the values (mass of electron, velocity), you can calculate the wavelength of the electron.
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What is the frequency of light having a wavelength of 447 nm?
The frequency of light with a wavelength of 447 nm can be calculated using the equation: frequency = speed of light / wavelength. Plugging in the values, the frequency is approximately 6.71 x 10^14 Hz.
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The frequency of a sound wave can be calculated using the formula: frequency = velocity / wavelength. Plugging in the values given, we get frequency = 341 m/s / 0.8 m = 426.25 Hz. Therefore, the frequency of the sound wave is 426.25 Hertz.
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What is the frequency of light having a wavelength of 447 nm?
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Calculate the frequency of a wave having a velocity of 15 m s and wavelength of 3 m?
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What is the frequency of a sound wave having a velocity of 341 meters and wavelength of 0.8 meters?
The frequency of a sound wave can be calculated using the formula: frequency = velocity / wavelength. Plugging in the values given, we get frequency = 341 m/s / 0.8 m = 426.25 Hz. Therefore, the frequency of the sound wave is 426.25 Hertz.
Why is it impossible to know precisely the velocity and position of an electron at the same time.?
This is because of the Heisenberg uncertainty principle. It is a part of quantum mechanics. It has to do with an electron having properties of both a particle and and wave. If you only imagine an electron to be a particle, this can be somewhat explained by the process of measuring the position or velocity of the electron. If the data is measured with light, then when a photon hits the electron, it changes the electrons speed and position. We may be able to find one, but in the process, the other will be changed.
Would a photon having a wavelength of 275 nm produce the photoelectric effect in lead?
Yes, a photon with a wavelength of 275 nm has enough energy (greater than the work function of lead) to eject an electron and produce the photoelectric effect in lead.
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The wavelength of colors in the visible spectrum ranges from approximately 400 to 700 nanometers. This corresponds to violet having the shortest wavelength and red having the longest wavelength.
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They are both transverse waves, albeit having different wavelength and frequency. I think that velocity of the waves will also be different as x-rays travel at the speed of light.
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Velocity is a vector; having direction. So, when changing direction constatly to have velocity a tangent can be drawn to the constantly changing path of the object having velocity.
