Coulomb's law of electrostatics force in vector form?

Answer 1

consider a two like charge q1 and q2 are present a and bpoint as distance R apart

let F12vectorbe a force of charge q1and q2and F21be the force of charge q2and q1

f12

Answer 2

Coulomb's law states that the force ( \textbf{F} ) between two point charges ( q_1 ) and ( q_2 ) separated by a distance ( r ) is given by ( \textbf{F} = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2} \hat{r} ), where ( \hat{r} ) is the unit vector in the direction of ( q_2 ) from ( q_1 ).

Answer 3

is directly proportional to product of magnitude of charges and inversely proportional to square of distance between them.

Answer 4

9*10^9 times Q1.Q2/r^2