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The station with a signal at 90.5 MHz would have higher energy waves compared to AM radio stations like 540 kHz. This is because the energy of an electromagnetic wave is directly proportional to its frequency, and higher frequencies have higher energy.

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Q: Are and 90.5 MHZ which station signal has Waves with higher energy?
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Which station's signal has waves with higher energy?

x - rays


What station would have waves with higher energy 90.5 MHz or 107.1 MHz?

107.1 MHz has higher energy photons. The photon energy increases directly proportional to frequency. However if the station operating on 90.5 MHz transmitter's power is 1.184 times or higher than that of the station operating on 107.1 MHz transmitter's power, then the 90.5 MHz signal will have higher energy because the additional photons makeup the difference. The total energy in electromagnetic radiation is the product of the energy per photon and the number of photons (i.e. amplitude of the wave) in the radiation.


Electromagnetic waves with the highest energy have the?

Electromagnetic waves of higher energy have a higher frequency and a smaller wavelength.Electromagnetic waves of higher energy have a higher frequency and a smaller wavelength.Electromagnetic waves of higher energy have a higher frequency and a smaller wavelength.Electromagnetic waves of higher energy have a higher frequency and a smaller wavelength.


What type of energy transfer occurs in a radio?

In a radio, energy transfers through electromagnetic waves. The electrical signal from the radio station is converted into electromagnetic waves, which travel through space and are picked up by the radio's antenna, converting them back into sound waves that we can hear.


Is it true that the transmitter of a radio station combines an electronic signal with a sound waves?

Yes, a radio transmitter converts an electronic signal (such as audio from a microphone) into radio frequency (RF) waves. These RF waves are then transmitted through antennas as electromagnetic radiation, which can be converted back into sound waves by a receiver like a radio or smartphone.


Explain why the energy of infrared waves is greater than the energy of radio waves?

The energy of infrared waves is greater than the energy of radio waves. This is because infrared waves has a smaller wavelength compared to radio waves. The smaller the wavelength, the higher the energy.


Trace the energy transformations from a radio signal to music you hear?

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Which will have more energy a high frequency waves or a low-frequency wave?

High frequency waves will have more energy than low-frequency waves. This is because energy is directly proportional to frequency in waves - the higher the frequency, the higher the energy.


What kid of energy does a microphone use in and out?

A microphone typically converts acoustic energy (sound waves) into electrical energy (signal) when it receives sound waves (input). Then, it uses electrical energy to transmit the signal to a recording device or amplifier (output).


What Component of electromagnetic waves that does vary?

The frequency of electromagnetic waves varies, which is determined by the energy of the wave. Higher energy waves have higher frequencies and shorter wavelengths, while lower energy waves have lower frequencies and longer wavelengths.


Does radio waves have the lowest energy per photon?

No, radio waves have the lowest frequency on the electromagnetic spectrum, but they do not necessarily have the lowest energy per photon. The energy of a photon is determined by its frequency, with higher frequencies corresponding to higher energies. Therefore, photons from higher frequency waves such as gamma rays have higher energy per photon compared to radio waves.


How do you compare the energy of two different waves?

You can compare the energy of two waves by calculating the square of their amplitudes. The wave with the higher amplitude will have more energy. Additionally, you can compare the frequencies of the waves - higher frequency waves generally carry more energy than lower frequency waves.