0
An arrow shot straight up into the air reached height of 75m with what velocity did it leave the bw how long was the arrow in the air?
Wiki User
∙ 14y ago
To find the initial velocity of the arrow, you can use the equation Vf^2 = Vi^2 + 2gh, where Vf is the final velocity (0 m/s at the top of the flight), Vi is the initial velocity, g is the acceleration due to gravity, and h is the height reached (75m). Solve for Vi to get the initial velocity. To find the time the arrow was in the air, you can use the equation h = Vit - 0.5g*t^2, where t is the time in the air. Plug in the known values to solve for t.
Add your answer:
Earn +20 pts
An arrow is shot straight up at an initial velocity of 200 meters per seconds. How long will it be before beginning to fall?
The arrow will begin to fall when its velocity becomes negative, which will happen after it reaches its maximum height and starts to descend. The time it takes for the arrow to reach its peak height can be calculated using the formula: time = (final velocity - initial velocity) / acceleration. After reaching the peak, the arrow will take the same amount of time to fall back down.
When an arrow is used to show velocity what does the arrow tell you?
The arrow's direction indicates the velocity's direction, while the arrow's length represents the velocity's magnitude.
Am arrow is shot straight up at an initial velocity of 250 m s how long will it take to hit the ground?
Assuming no air resistance, the arrow will take approximately 5 seconds to hit the ground because it will reach its maximum height before falling back down due to gravity. The total time for the arrow to travel up and back down is twice the time it takes to reach the maximum height.
An arrow is shot straight up at an initial velocity of 200 ms. How long will it be in the air before beginning to fall?
The time the arrow will be in the air before beginning to fall can be calculated using the formula t = (final velocity - initial velocity) / acceleration. Since the arrow is shot straight up, the final velocity at the top of its flight is 0. Given the initial velocity of 200 ms and acceleration due to gravity of -9.81 m/s^2, the time in the air before beginning to fall is approximately 20.4 seconds.
If an archer shoots an arrow straight up with an initial velocity magnitude of 100.0 ms After 5.00 seconds the velocity is 51.0 ms. At what rate is the arrow decelerated?
The average deceleration of the arrow can be calculated using the formula: average deceleration = (final velocity - initial velocity) / time. Plugging in the values gives an average deceleration of (51.0 - 100.0) / 5.00 = -9.8 m/s^2. This negative value indicates that the arrow is decelerating due to the acceleration of gravity.
An arrow is shot straight up at an initial velocity of 200 meters per seconds. How long will it be before beginning to fall?
The arrow will begin to fall when its velocity becomes negative, which will happen after it reaches its maximum height and starts to descend. The time it takes for the arrow to reach its peak height can be calculated using the formula: time = (final velocity - initial velocity) / acceleration. After reaching the peak, the arrow will take the same amount of time to fall back down.
When an arrow is used to show velocity what does the arrow tell you?
The arrow's direction indicates the velocity's direction, while the arrow's length represents the velocity's magnitude.
Am arrow is shot straight up at an initial velocity of 250 m s how long will it take to hit the ground?
Assuming no air resistance, the arrow will take approximately 5 seconds to hit the ground because it will reach its maximum height before falling back down due to gravity. The total time for the arrow to travel up and back down is twice the time it takes to reach the maximum height.
An arrow is shot straight up at an initial velocity of 250ms How long will it take to hit the ground?
This is a velocity question so u need to use uvaxt
An arrow is shot straight up at an initial velocity of 200 ms. How long will it be in the air before beginning to fall?
The time the arrow will be in the air before beginning to fall can be calculated using the formula t = (final velocity - initial velocity) / acceleration. Since the arrow is shot straight up, the final velocity at the top of its flight is 0. Given the initial velocity of 200 ms and acceleration due to gravity of -9.81 m/s^2, the time in the air before beginning to fall is approximately 20.4 seconds.
If an archer shoots an arrow straight up with an initial velocity magnitude of 100.0 ms After 5.00 seconds the velocity is 51.0 ms. At what rate is the arrow decelerated?
The average deceleration of the arrow can be calculated using the formula: average deceleration = (final velocity - initial velocity) / time. Plugging in the values gives an average deceleration of (51.0 - 100.0) / 5.00 = -9.8 m/s^2. This negative value indicates that the arrow is decelerating due to the acceleration of gravity.
What is represented by the length of the arrow in a vector arrow?
Velocity.
An arrow in flight has an initial velocity of 65 meters per second and 10 seconds later it has a velocity of 35 meters per second Which is the acceleration of the arrow?
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
When was Straight as an Arrow created?
Straight as an Arrow was created on 2008-11-30.
How do you solve this An arrow is fired into the air with an initial velocity of 160 feet per second. The height in feet of the arrow t seconds after it was shot into the air is given by the function?
If the arrow was fired in a direction making an angle x with the horizontal, and assuming that acceleration due to gravity is 32 feet per second^2 ijn the downward direction, then its height at time t iss(t) = 160*sin(x)*t - 16*t^2.
What is changing velocity on a motion diagram showing?
Changing velocity on a motion diagram is represented by changing arrow lengths or orientations. A longer arrow indicates a higher velocity, while a shorter arrow indicates a lower velocity. Changes in orientation signify changes in direction of motion.
When an archer shoots an arrow straight up with an initial velocity magnitude of 100.0 ms. After 5.00 s the velocity is 51.0 ms. At what rate is the arrow decelerated?
The change in velocity is 51-100 = -49 m/s This occurred over a period of 5 seconds so The (negative) acceleration - aka - deceleration is (-49 m/s)/(5 s) = -9.8 m/s²
