Wiki User
∙ 11y ago240 ohms
Wiki User
∙ 11y agoUsing Ohm's Law (V=IR), we can rearrange the formula to solve for resistance: R = V/I. Plugging in the values, R = 120 volts / 0.5 amps = 240 ohms. Thus, the resistance of the alarm clock is 240 ohms.
Anonymous
240OHMS
Anonymous
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Current flow can be calculated using Ohm's Law, which states that current (I) is equal to the voltage (V) divided by the resistance (R), represented by the formula I = V/R. By measuring the voltage across a circuit and knowing the resistance, you can calculate the current flowing through it.
When you increase the resistance in a circuit, the current (amps) in the circuit will decrease. This is because Ohm's Law states that current is inversely proportional to resistance, so as resistance increases, current decreases.
The current in each branch of a parallel circuit is determined by the voltage across that branch and the resistance of the components in that branch. According to Ohm's Law (I = V/R), the current flowing through a branch is inversely proportional to the resistance and directly proportional to the voltage. Each branch in a parallel circuit will have its own current based on the components connected to it.
Increasing the length of wire in a series circuit increases the overall resistance in the circuit, which reduces the current flowing through the circuit. This results in a decrease in the brightness of any connected bulbs or the speed of any connected motors, as the components receive less energy due to the increased resistance.
The ammeter does affect the flow of current in a circuit, however, the resistance of the ammeter is so small in comparison to the circuit that the effect is negligible. It is connected in series.
The resistance of the load is what causes an electric current to flow in a circuit.
The current in a 220 volt circuit depends on the resistance of the load connected to it. Ohm's Law (I = V/R) states that current (I) is equal to voltage (V) divided by resistance (R). So, the current will vary based on the resistance of the circuit.
Current will be decreased because of the resistance of the ammeter added to the circuit's resistance. In other words total resistance increases.
To solve any D.C. circuit by using Thevenin Theorem,First of all load resistance RL is disconnected from the circuit and open circuit voltage across the circuit is calculated (known as Thevenin equivalent voltage)Secondly, the battery is removed by leaving behind its internal resistance. Now we calculate equivqlent resistance of the circuit ( called Thevenin equivalent resistance).Now we connect Thevenin Voltage in series with Equivalent resistance of the circuit and now connect load resistance across this circuit to calculate current flowing through the load resistance.Whereas in the case of using Norton theorem, we again remove the load resistance if any, and then short circuit these open terminals and calculate short circuit current Isc.Second step is same as in Thevenin theorem i.e. remove all sources of emf by replacing their internal resistances and calculate equivqalent resistance of the circuit.Lastly, join short circuit current source in parallel with equivalent resistance of the circuit. Now, we can calculate votage across the resistance which was connected in parallel with Isc.So, by knowing the open circuit voltage, we can calculate current flowing the resistance and on the other hand , by knowing the short curcuit current , we can calculate voltage across the resistance.
:) It's connected together
If the circuit is carrying current then that means that the load (resistance) is in the circuit. if an ohm meter is connected in the live circuit then there would be some voltage drop at the ohm meter but as the meter has very less resistance, this would damage the instrument.
Use Ohm's Law. In this case, multiply the resistance by the current.
The current in amps (A) depends on the resistance in the circuit. Using Ohm's Law (I = V/R), you can calculate the current (I) by dividing the voltage (V) by the resistance (R). Without knowing the resistance in the circuit, we cannot determine the exact current at 320V.
Because it is a metal so has lots of free electrons which when connected to a circuit detach from the atoms and move around the circuit. This produces a high current, so resistance will be low as current is high.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
If you are looking for the resistance of each resistor in either a series circuit or a parallel circuit you must measure the current I and the voltage V for each resistor. Then calculate its resistance using Ohms Law R = V / I where I = current (Amps), V = voltage (Volts) and R= resistance (Ohms).