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A rock dropped on the moon will increase its speed from 0 ms to 8.15 ms in about 5 seconds. What is the acceleration of the rock?
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When rock dropped on the moon will increase its speed from 0 ms to 8.15 ms in about 5 seconds what is the acceleration of the rock?
The acceleration of the rock would be (1.63 , \text{m/s}^2) (calculated by dividing the change in velocity by the time taken).
A rock dropped on the moon will increase its speed from 0 m s to 4.9 m s in about 3 seconds what is the acceleration of the rock?
The acceleration of the rock is calculated by dividing the change in velocity by the time taken. In this case, the change in velocity is 4.9 m/s and the time taken is 3 seconds. Thus, the acceleration of the rock is 4.9 m/s^2.
An increase in speed is sometimes called?
acceleration
When acceleration and velocity are in the same direction the speed will?
In that case, the speed will increase.
Will acceleration only speed up an object?
No, acceleration can speed up an object, slow it down, or change its direction. Acceleration is a vector quantity that includes both the rate of change of speed and the direction in which the object is moving.
A rock dropped on the moon will increase its speed from 0 ms its starting speed when first dropped to 4.9 ms in about 3 seconds What value do you calculate for the magnitude of the acceleration o?
1.63 m/s2
A rock dropped on the moon will increase its speed from 0 ms to 4.9 ms in about 3 seconds. What value do you calculate for the magnitude of the acceleration of gravity on the moon?
Acceleration = (change in speed) divided by (time for the change)= (4.9) / 3 = 1.63 m/s2(rounded)
When rock dropped on the moon will increase its speed from 0 ms to 8.15 ms in about 5 seconds what is the acceleration of the rock?
The acceleration of the rock would be (1.63 , \text{m/s}^2) (calculated by dividing the change in velocity by the time taken).
A rock dropped on the moon will increase its speed from 0 m s to 4.9 m s in about 3 seconds what is the acceleration of the rock?
The acceleration of the rock is calculated by dividing the change in velocity by the time taken. In this case, the change in velocity is 4.9 m/s and the time taken is 3 seconds. Thus, the acceleration of the rock is 4.9 m/s^2.
A rock dropped on the moon will increase its speed from 0 ms its starting speed when first dropped to 49 ms in about 3 seconds What value do you calculate for the magnitude of the acceleration o?
Acceleration = (change in speed) divided by (time for the change).From the figures given in the question, the acceleration is ( 49/3 ) = 16.33 m/sec2 .There's no way that this is happening on the moon. That acceleration is about 67% greaterthan the acceleration of gravity on the earth's surface. It should be about 83% less, or about 1.63 m/sec2.I see the problem now. The '49' in the question should be '4.9'.apex- 1.63 m/s2
A car accelerates to pass a truck going from 20miles per second to 29miles per second in 3 seconds what was the acceleration?
So acceleration is an increase of speed every second. The increase of speed was 9miles/sec and this was over 3 seconds. Therefore there was an acceleration of 3 miles/second every second i.e. 3m/s2
A rock dropped on the moon will increase its speed from 0 its starting speed to 8.15 in about 5 seconds If you were standing on the moon measuring the rock's motion what would you measure?
You would observe the rock falling from rest and accelerating to a speed of 8.15 m/s in about 5 seconds due to the moon's gravity. This motion can be described using equations of motion, such as the equations of uniformly accelerated motion.
An increase in speed is sometimes called?
acceleration
When a body undergoes an acceleration does its speed increase or decrease?
Both. Acceleration is a change in speed.
When acceleration and velocity are in the same direction the speed will?
In that case, the speed will increase.
What is an increase in speed callled?
acceleration
If a rock is dropped and it's speed increases from 0 to 4.9 in about 3 seconds. what is the acceleration?
Assuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
