The formula to calculate the force on a charge in an electric field is: ( F = qE ), where ( F ) is the force, ( q ) is the charge, and ( E ) is the electric field strength. Given ( F = 3.0 \times 10^{-3} , \text{N} ) and ( E = 2.0 , \text{N/C} ), we can rearrange the formula to solve for the charge, yielding ( q = \frac{F}{E} = \frac{3.0 \times 10^{-3}}{2.0} = 1.5 \times 10^{-3} , \text{C} ). Thus, the magnitude of the charge is ( 1.5 \times 10^{-3} , \text{C} ).
An object pulled inward in an electric field is moving in the direction of the electric field lines. The object experiences a force due to the electric field that causes it to accelerate towards the source of the field, typically a positive charge. The magnitude and direction of the force depend on the charge of the object and the electric field strength.
The magnitude of an electric field is defined as the force per unit charge experienced by a test charge placed in the field. It is measured in units of newtons per coulomb (N/C). This magnitude represents the strength of the electric field at a particular point.
The electric charge of an electron is -1.602 x 10^-19 coulombs. This negative charge is equal in magnitude but opposite in sign to the charge of a proton.
Another factor that determines the magnitude of the electric potential is the amount of charge on the particle creating the electric field. The electric potential is directly proportional to the charge creating the field.
The magnitude of the electric force between particles is also determined by the amount of charge on each particle. The greater the charge, the stronger the electric force.
Yes, the electric field created by a point charge is directly proportional to the magnitude of the charge. As the charge increases, the electric field strength at a given distance from the charge also increases.
An object pulled inward in an electric field is moving in the direction of the electric field lines. The object experiences a force due to the electric field that causes it to accelerate towards the source of the field, typically a positive charge. The magnitude and direction of the force depend on the charge of the object and the electric field strength.
The magnitude of an electric field is defined as the force per unit charge experienced by a test charge placed in the field. It is measured in units of newtons per coulomb (N/C). This magnitude represents the strength of the electric field at a particular point.
The electric charge of an electron is -1.602 x 10^-19 coulombs. This negative charge is equal in magnitude but opposite in sign to the charge of a proton.
Another factor that determines the magnitude of the electric potential is the amount of charge on the particle creating the electric field. The electric potential is directly proportional to the charge creating the field.
The magnitude of the electric potential is dependent upon the particle's charge and the electric field strength.
The magnitude of the electric force between particles is also determined by the amount of charge on each particle. The greater the charge, the stronger the electric force.
The electric charges of the proton and electron are equal in magnitude (size, strength), and opposite in sign.
A proton has a positive charge which is equal in magnitude but opposite to the charge on an electron, which is negative.
The magnitude of the electric field above an isolated charge can be calculated using the formula E = k*q/r^2 where k is Coulomb's constant, q is the charge, and r is the distance. The direction of the electric field is radially outward from the charge.
Yes, because each proton carries a positive electric charge that is equal in magnitude to the negative electric charge on each electron.
The shape of the electric field is altered. The fields will react by either repelling or attracting each other.