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A ball thrown up vertically returns to the thrower after 6 seconds find the velocity with which it was thrown up?
Wiki User
∙ 8y ago
The velocity changes from [ V upward ] to [ V downward ].
The total change in velocity is [ 2V ].
Acceleration = (change in velocity) divided by (time for the change) = 2V/6
But the acceleration is just the acceleration of gravity = 9.8 meters / sec2 .
9.8 = 2V / 6
2V = 58.8
V = 29.4 meters per second upward
Wiki User
∙ 14y ago
To find the initial velocity, we first calculate the time it takes for the ball to reach the highest point, which is half of the total time taken (t/2 = 6/2 = 3 seconds). Then, we use the equation v = gt, where v is the initial velocity, g is the acceleration due to gravity (9.81 m/s^2), and t is the time taken to reach the highest point (3 seconds). So, v = 9.81 m/s^2 * 3 s = 29.43 m/s.
Wiki User
∙ 8y agoi need the deceleration....
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A ball is thrown vertically upward it returns back in the hand of the thrower in 60 seconds how high does it go?
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