The weight of an object of mass 2m is 2mg. Weight is directly proportional to mass, so if you double the mass, you double the weight.
Well, honey, 0.2 mg is definitely not the same as 1 mg. It's like asking if a drop in the ocean is the same as the whole darn ocean. One is a fraction of the other, so don't go confusing your doses unless you want some unexpected side effects.
The word equation for the formula 2Mg O2 yields 2MgO would be: "Two magnesium atoms react with one oxygen molecule to produce two magnesium oxide compounds."
0.5 grams is larger than 0.5 milligrams. There are 1000 milligrams in one gram.
Terminal velocity of a falling object can be calculated using the formula: ( v = \sqrt{\frac{2mg}{C\rho A}} ), where ( v ) is the terminal velocity, ( m ) is the mass of the object, ( g ) is the acceleration due to gravity, ( C ) is the drag coefficient of the object, ( \rho ) is the density of air, and ( A ) is the cross-sectional area of the object.
The weight of an object of mass 2m is 2mg. Weight is directly proportional to mass, so if you double the mass, you double the weight.
No. 2mg means "two miligrams". 0.2mg means "two-tenths milligram". So 2mg is 10 times more than 0.2mg.
Yes, 2000mcg is more than 50mg. 2000mcg (micrograms) is equivalent to 2mg, which is greater than 50mg.
If it is 2mg xanax it doesn't matter if they are round, square, oval or bars. There are different manufactures that produce xanax (alprazalam) and if the bottle says 2mg then its 2mg.
The equianalgesic dosage of 2mg levorphanol taken by mouth is about 15mg of hydrocodone. So, levorphanol is about 8 times more potent than hydrocodone by weight.
Well, honey, 0.2 mg is definitely not the same as 1 mg. It's like asking if a drop in the ocean is the same as the whole darn ocean. One is a fraction of the other, so don't go confusing your doses unless you want some unexpected side effects.
no 2,000 mg is about 1,998mg more.
aboslutely 2mg is less than 088mg
2mg hydromorphone is equivalent to about 5-6mg oxycodone. Hydromorphone is more for the milligram but 6mg Oxycontin will probably produce a stronger high than 2mg hydromorphone. Or at least it has in my experience.
The oxidation half-reaction for the conversion of 2Mg to MgO is: 2Mg(s) -> 2Mg^2+(aq) + 4e^-
Hmmmm is that a trick question? Answer: 2mg
hydromorphone 2mg