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It depends on the values of B and C but without that knowledge, it is 7*B*C.
Rb is rubidium, O is oxygen. They will combine to form Rb2O which is called rubidium oxide.
#include<stdio.h> #include<conio.h> void main() { int i,c,n; printf("Enter the number of terms you want which are divisible by 7"); scanf("%d",&n); c=0; for(i=7;;i+=7) { printf("\n %d ",i); c++; if(c==n) break; } getch(); }
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