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The valence electron configuration of selenium is 4s2 4p4, meaning it has 6 valence electrons.
Selenium has 6 electrons in its outermost shell.
H2Se has six valence electrons. Each hydrogen contributes one valence electron, and selenium contributes four.
6. If you look at the electron configuration of Selenium, it is [Ar]3d^10 4s^2 4p^4, meaning 10 electrons are located in the 3rd shell, and a total of 6 are located in the 4th shell, the highest energy shell. The electrons in the 4s and 4p shells combined are the valence electrons, meaning there are 6 valence electrons on Selenium.
Two- Since it has six valence electrons, it can form two covalent bonds, making the valence two. If it is easier to think about it this way, eight valence electrons would stabilize the element. Eight minus six is two, giving us the same answer as before.