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I guess I would first make 2 types of clarifications for this questions.

First- We have to make the distinction between molecule geometry which is usually sort of what you see in a Lewis dot structure (2D), to molecule shape which is where VSEPR comes in (3D)

Second- AX?, AX-(what), AX3, AX5, AX4...

Either way usually in VSEPR, each X is trying to get as much space as possible in a 3D form, thus a tetrahedral form will be preferred over a square planar. Each X will be approximately 109.5 degrees apart from each other, instead of 90 degrees.

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11y ago
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1mo ago

Molecules of type AX4 often take a tetrahedral form due to the presence of four electron pairs around the central atom, leading to a geometry with minimal repulsion between the electron pairs. In a tetrahedral arrangement, the bond angles are around 109.5 degrees, which allows for maximum separation between the bonding pairs.

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12y ago

the only repulsion happening is between the substituents,

so it is in its optimal (lowest) energy state as the tetrahedral form.

Square planar molecules (like AX4E2) contain 2 lone pairs that produce electron to bond repulsion that result in the lowest energy form to be square planar.

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Q: Why molecules of the type AX4 take a tetrahedral form often than the square planar form?
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