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Aluminium is formed at the cathode because the Al ions (Al3+) within the electrolyte are attracted to form aluminium metal by gaining 3 electrons.

The metal is molten due to the high temperature of the cells.

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12y ago
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4mo ago

Aluminum ions collect at negative electrodes during electrolysis because they are positively charged and are attracted to the negatively charged electrode. This is due to the principle of opposite charges attracting each other.

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14y ago

metals lose electrons and become positively charged.. and are attracted to the negative electrode (cathode) this is why metals deposit at the cathode.

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12y ago

Aluminium ions have a 3+ charge so are therefore attracted to the cathode, which has a negative charge.

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12y ago

As Aluminium becomes as positive ion by losing three electrons.

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13y ago

No, Cathode

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Anonymous

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4y ago

becuase i dotnt know tellme

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Q: Why do the aluminum ions collect at negative electrodes?
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An electrolytic cell is made with zinc and aluminum electrodes Which of the following happen at the cathode of this cell?

At the cathode of the electrolytic cell with zinc and aluminum electrodes, the reduction of aluminum ions into aluminum metal will occur. Aluminum ions gain electrons to form solid aluminum metal, while zinc remains unchanged as it does not participate in the reaction at the cathode.


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What happens at the negative electrode during the electrolysis of molten aluminium?

At the negative electrode during the electrolysis of molten aluminum, aluminum ions in the molten aluminum are reduced to form liquid aluminum metal. This process occurs as a result of the transfer of electrons to the aluminum ions, causing them to gain electrons and be converted into the metallic form.


What is the equation for molten aluminum chloride is electrolyzed?

The electrolysis of molten aluminum chloride involves the migration of Al3+ and Cl- ions to the respective electrodes. At the cathode, aluminum ions are reduced to form aluminum metal, while at the anode, chloride ions are oxidized to form chlorine gas. The overall reaction can be represented as 2Al3+ + 6e- -> 2Al (reduction at cathode) and 2Cl- -> Cl2 + 2e- (oxidation at anode).


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