Marce123
Find the atomic or molecular weight of each and multiply it by the number of moles.
atomic weight of carbon is 12 g/mole.
atomic weight of chlorine is 35.45 g/mole
molecular weight of fructose is 180.16 g/mole
So just find the total grams.
10 moles Carbon * 12g/mole Carbon = 120 grams carbon
3 moles Chlorine * 35.45g/mole Chlorine = 106.35 grams Chlorine
1 mole Fructose * 180.16 g/mole Fructose = 180.16 grams Fructose
So the answer is 1 mole of fructose.
Wiki User
∙ 14y ago10 mol of C has the largest mass, as carbon has a higher Atomic Mass compared to chlorine and the elements in fructose. The mass of one mole of carbon is about 12 grams, while one mole of chlorine is about 35.5 grams, and one mole of fructose is around 180 grams.
To convert 0.10 mol of NaNO3 to grams, you need to use the molar mass of NaNO3, which is 85 g/mol. Multiplying 0.10 mol by the molar mass will give you the answer: 0.10 mol x 85 g/mol = 8.5 grams of NaNO3.
The molecular mass of H2SO4 (sulfuric acid) is approximately 98.08 g/mol. This value is calculated by adding together the atomic masses of two hydrogen atoms, one sulfur atom, and four oxygen atoms in the molecule.
First, calculate the mass of calcium in CaCO3: m(Ca) = (molar mass of Ca / molar mass of CaCO3) x mass of CaCO3. Then, calculate the mass percent of calcium: (mass of Ca / total mass of supplement) x 100. Given that molar mass of Ca = 40.08 g/mol and molar mass of CaCO3 = 100.09 g/mol, the mass percent of calcium will be (40.08 / 100.09) x 1.15 / 2.70 x 100.
To calculate the mole fraction of glucose, first find the moles of each component by dividing its mass by its molar mass. The molar mass of glucose (C6H12O6) is 180 g/mol. The moles of glucose is 180g / 180 g/mol = 1 mol. The moles of water is 162g / 18 g/mol = 9 mol. The total moles in the solution is 1 + 9 = 10 mol. The mole fraction of glucose is 1 mol / 10 mol = 0.1.
The molar mass of helium is 4 g/mol. This means that 1 mole of helium has a mass of 4 grams. Since 2.5 moles of helium have a mass of 10 grams, the atomic mass of helium is 4 grams/mol.
Since magnesium and helium do not form elemental molecules, a mole of these elements is the same as a gram atomic mass, which is 24.305 for magnesium and 4.00260 for helium. The gram molecular mass for sucrose is 342.30. Therefore, the mass of: A. 3 moles of magnesium is 72.915 grams; B 1 mole of sucrose (C12H22O11) is 342.30 grams; and C. 10 moles of helium is 40.0260 grams. The largest of these is obviously the single mole of sucrose.
To convert 0.10 mol of NaNO3 to grams, you need to use the molar mass of NaNO3, which is 85 g/mol. Multiplying 0.10 mol by the molar mass will give you the answer: 0.10 mol x 85 g/mol = 8.5 grams of NaNO3.
The molar mass of H2 is 2 g/mol. To find the mass of 5 moles of H2, you would multiply the molar mass by the number of moles: 2 g/mol * 5 mol = 10 grams.
The molar mass of iodine (I) is approximately 127 grams/mol. So, for 10 moles of iodine atoms, the mass would be 10 moles * 127 grams/mol = 1270 grams.
To calculate the mass of CdS, we need to have the molar mass of CdS. Cadmium (Cd) has a molar mass of approximately 112.41 g/mol, and sulfur (S) has a molar mass of approximately 32.07 g/mol. Adding these together, we get a molar mass of approximately 144.48 g/mol for CdS. To find the mass of 2.50 x 10^-2 mol of CdS, we would multiply the number of moles by the molar mass: (2.50 x 10^-2 mol) x (144.48 g/mol) = 3.61 g of CdS.
Convert the 200 mol of water to kilograms of water.
Io (the moon of Jupier) has a mass of 8.9319×1022 kg
The molar mass of barium hydride (BaH2) is 137.33 g/mol. Therefore, the mass of 4.80 mol of barium hydride would be 4.80 mol x 137.33 g/mol = 659.184 g.
The molecular mass of H2SO4 (sulfuric acid) is approximately 98.08 g/mol. This value is calculated by adding together the atomic masses of two hydrogen atoms, one sulfur atom, and four oxygen atoms in the molecule.
First, calculate the mass of calcium in CaCO3: m(Ca) = (molar mass of Ca / molar mass of CaCO3) x mass of CaCO3. Then, calculate the mass percent of calcium: (mass of Ca / total mass of supplement) x 100. Given that molar mass of Ca = 40.08 g/mol and molar mass of CaCO3 = 100.09 g/mol, the mass percent of calcium will be (40.08 / 100.09) x 1.15 / 2.70 x 100.
To calculate the mole fraction of glucose, first find the moles of each component by dividing its mass by its molar mass. The molar mass of glucose (C6H12O6) is 180 g/mol. The moles of glucose is 180g / 180 g/mol = 1 mol. The moles of water is 162g / 18 g/mol = 9 mol. The total moles in the solution is 1 + 9 = 10 mol. The mole fraction of glucose is 1 mol / 10 mol = 0.1.
To find the number of Cl ions in FeCl3, we first need to calculate the molar mass of FeCl3. Iron (Fe) has a molar mass of approximately 55.85 g/mol, and chlorine (Cl) has a molar mass of approximately 35.45 g/mol. Therefore, the molar mass of FeCl3 is 55.85 + (3 * 35.45) = 126.2 g/mol. Next, we determine how many moles of FeCl3 are present in 50.0 g by dividing the mass by the molar mass: 50.0 g / 126.2 g/mol ≈ 0.396 mol. Since there are 3 Cl ions in every FeCl3 molecule, there are approximately 0.396 mol * 3 = 1.19 mol of Cl ions. Finally, we use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of Cl ions: 1.19 mol * 6.022 x 10^23 Cl molecules/mol = approximately 7.16 x 10^23 Cl ions.