[Xe] 4f3 6s2
The electron configuration of americium is [Rn]5f7.7s2.
Argon has the same electron configuration as N3. Both have 10 electrons with the electron configuration 1s2 2s2 2p6.
neon
Alkali metal atoms need to lose one electron to achieve the stable electron arrangement of the nearest noble gas. This is because the noble gases have a full valence shell, which is more stable. By losing an electron, the alkali metal atoms achieve a full valence shell and become more stable.
[Xe] 4f3 6s2
Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration. Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration.
The electron configuration of americium is [Rn]5f7.7s2.
Caesium (Cs) has 55 electrons, and it will need to lose 1 electron to achieve a noble gas electron configuration. This is because Cs is in Group 1 of the periodic table, so losing 1 electron will leave it with the same electron configuration as the noble gas element in the previous period (Xenon).
I assume you mean the Nobel gas electron configuration abbreviation for barium.[Ne] 6s2=======
If you think to the electron configuration of promethium this begin with [Xe].
The noble gas that has the same electron configuration as the oxygen atom in a water molecule is neon (Ne). Both have a full valence shell with 8 electrons, making them stable and unreactive.
The Alkali Metals loose one electron in order to achieve a nobel gas configuration.
Helium IS a Nobel gas and heads that group. It may not have the full 8 electron octet, but it is just as naturally non-reactive as the other Nobel gases.
Cs and Be^3+ ions do not have a noble gas electron configuration. Cs loses one electron to achieve a stable electron configuration like Xe, and Be^3+ loses three electrons to achieve a stable configuration like He.
No, potassium does not have a noble gas electron configuration. The noble gas configuration for potassium would be [Ar] 4s¹, but instead, potassium has the electron configuration 1s² 2s² 2p^6 3s² 3p^6 4s¹.
nobel gas is a gas that cannot react with another gas