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What would be the orbital speed and period of a satellite in orbit 1.44 times 10 to the power of 3m above earth?
Wiki User
∙ 12y ago
The orbital speed would be approximately 7.63 km/s and the period would be approximately 95.59 minutes for a satellite orbiting Earth at an altitude of 1.44 x 10^3 m. These values can be calculated using the formula for orbital speed (v = √(GM/r)) and the formula for orbital period (T = 2π√(r^3/GM)), where G is the gravitational constant, M is the mass of Earth, and r is the altitude of the satellite above Earth's surface.
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