Salt and water. =)
A neutraliZation reaction is when you mix an acid and a base/alkali. They neutralize each other and water and salt are produced.
A good example of this:
NaOH = Sodium hydroxide (lye) is our base
HCl = Hydrochloric acid is.. well, our acid
NaOH + HCl = NaCl + H2O
NaCl = Sodium chloride (salt)
H2O = Water
Why this happens: The different ions are positively or negatively charged and will bond accordingly to become neutral compounds. Here is a simplified breakdown..
Na(+) OH(-1) + H(+) Cl(-) = NaCl + H2O
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In a neutralization reaction, an acid and a base react to form salt and water as the two products. The acid reacts with the base to form a salt, while the hydrogen ions from the acid combine with the hydroxide ions from the base to form water.
If it's between an acid and a base then the products are a salt and water
eg Mg(OH)2 + 2HCl --> MgCl2 + 2H2O
If it's between an acid and a Carbonate then the products are a salt, water and CO2
eg: CaCO3 + 2HCl --> CaCl2 + H2O +CO2
There are a few more different reactions but these are the main two and the only ones I could remember :P
well it depends what two compounds you use
metal oxide + acid --> a salt + water
metal + acid --> a salt + hydrogen
The most likely products formed from the reaction between calcium carbonate and sodium metal are calcium oxide (CaO) and sodium carbonate (Na2CO3). Calcium carbonate will react with sodium metal to form calcium oxide, sodium carbonate, and carbon in the form of soot.
The main products of the reaction between methane and chlorine are chloromethane (CH3Cl) and hydrogen chloride (HCl).
In the reaction 2H2O2 -> 2H2O, the reactants are hydrogen peroxide (H2O2) and the products are water (H2O). The reaction involves the decomposition of hydrogen peroxide into water and oxygen gas.
When calcium bromide reacts with sodium carbonate, a double displacement reaction occurs. Calcium carbonate and sodium bromide are formed as the products. The balanced chemical equation for this reaction is CaBr2 + Na2CO3 -> CaCO3 + 2NaBr.
The stoichiometry of the reaction between sulfur dioxide and oxygen to produce sulfur trioxide is 2SO2 + O2 -> 2SO3. This means that 2 moles of SO3 are formed from 2 moles of SO2. Therefore, if 3 moles of SO2 are used, 3/2 = 1.5 moles of SO3 will be formed.