SukainaAli
A metal and a nonmetal would form an ionic bond. In an ionic compound, a metal ion would have a positive oxidation number equal to its ionic charge. A nonmetal would have a negative oxidation number equal to its ionic charge.
Examples:
NaCl oxidation numbers: sodium has an oxidation number of +1, chloride has an oxidation number of -1. So the overall charge of NaCl is zero.
CaCl2 oxidation numbers: calcium has an oxidation number of +2, the chloride ion has an oxidation of -1. Since there are two chloride ions, the total negative oxidation number is -2, so CaCl2 has an overall charge of zero.
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∙ 12y agoA metal ion typically has a positive oxidation number equal to its charge, while a non-metal ion typically has a negative oxidation number equal to its charge. For example, a sodium ion (metal) has a +1 oxidation number, and a chloride ion (non-metal) has a -1 oxidation number.
The subscript of the second ion identifies the oxidation state of the transition metal
Follow these 5 Rules1) The oxidation number of the atoms in a neutral molecule must add up to zero, and those in a charged ion must add up to the charge on the ion. 2) Alkali metal atoms (first column in the periodic table) have oxidation number +1, alkaline earth atoms (2nd column) have oxidation number +2.3) Fluorine always has oxidation number -1. Other halogens (next-to-last column in the periodic table) usually have oxidation number -1, except when they are bonded to oxygen or other halogens, when they can have positive oxidation numbers.4) Hydrogen has oxidation number +1 except in metal hydrides, such as LiH or CaH2, where Rule #2 takes precedence, and hydrogen has oxidation number -1.5) Oxygen has oxidation number -2, with two exceptions: In compounds where it is bonded to fluorine, Rule #3 takes precedence, and in compounds with O-O bonds, Rules #2 and #4 take precedence. So, for example, the oxidation number in OF2 is +2, and the oxidation number in peroxides such as H2O2 is -1 (and superoxides, the oxidation number is -1/2)It is also convenient to know the charge on these common ions:Nitrate is minus one: NO3-Hydroxide is minus one: OH-Sulfate is minus two: SO42-Carbonate is minus two: CO32-Phosphate is minus three: PO43-Ammonium is plus one: NH4+
To find the atomic weight of the metal, we first find the number of moles of metal by dividing its mass by its molar mass. Next, we find the number of moles of oxygen by dividing its mass by its molar mass. Since the metal is trivalent, we set up a ratio using their mole numbers to find the atomic weight of the metal.
The mass number of an element like calcium is the sum of the number of protons and neutrons in its nucleus. Calcium has 20 protons, so to find the mass number, you would look up the number of neutrons in the periodic table and add that to 20.
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Metal Oxidation
The oxidation number of an element can be found by referring to the periodic table and following the general rules and guidelines for assigning oxidation numbers to elements in compounds. The oxidation number reflects the charge an atom would have if all bonds were ionic.
For a neutral atom or compound, the oxidation number is always 0. For an ion, the overall oxidation number is its charge. If you need to find an oxidation number to a particular atom of a compound, there are two ways: working out the Lewis structures or balancing the charges.
The oxidation number of silver (Ag) is +1 and the oxidation number of oxygen (O) is -2. To find the oxidation number of phosphorus (P) in Ag3PO4, we can set up an equation: 3(+1) + x + 4(-2) = 0. Solving for x, we find that the oxidation number of phosphorus in Ag3PO4 is +5.
To find the oxidation number of chlorine, consider that chlorine typically has an oxidation number of -1 in its compounds. However, in certain situations, such as when bonded with oxygen or other halogens, chlorine can have different oxidation states. It's important to follow the usual oxidation number rules and balance the charges in the compound to determine the oxidation number of chlorine.
To find the oxidation number of copper (Cu) in CuO, consider that oxygen (O) usually has an oxidation number of -2. Since CuO is a neutral compound, the oxidation number of Cu can be calculated by setting up an equation where the sum of the oxidation numbers equals zero. In this case, the oxidation number of Cu in CuO is +2.
The oxidation number of Mg is +2. The oxidation number of O is -2, and since there are 6 oxygen atoms in Mg2Si2O6, the total oxidation number contributed by O is -12. The oxidation number of Si is +4. Therefore, to find the oxidation number of Mg in Mg2Si2O6, you can set up an equation as follows: 2x + 2(+4) + 6(-2) = 0, where x is the oxidation number of Mg. By solving this equation, you find that the oxidation number of Mg is +2 in Mg2Si2O6.
The oxidation number of Na in Na2CrO4 is +1 and the oxidation number of O in Na2CrO4 is -2. To find the oxidation number of Cr, we let x be the oxidation number: 2(+1) + x + 4(-2) = 0 x = +6 Therefore, the oxidation number of Cr in Na2CrO4 is +6.
The oxidation number of sulfur in H2S2O8 is +6. Each oxygen atom has an oxidation number of -2, and each hydrogen atom has an oxidation number of +1. By setting up an equation and solving for sulfur's oxidation number, you will find it to be +6.
To find the oxidation number for Zn in ZnSO4, you need to consider the oxidation numbers of the other elements. In ZnSO4, oxygen usually has an oxidation number of -2 and sulfur of +6. Since the compound is neutral, the sum of the oxidation numbers of all elements must equal zero. Hence, the oxidation number of Zn in ZnSO4 is +2.
For a neutral atom or compound, the oxidation number is always 0. For an ion, the overall oxidation number is its charge. If you need to find an oxidation number to a particular atom of a compound, there are two ways: working out the Lewis structures or balancing the charges.
The oxidation number of H in H2PO3^- is +1 because hydrogen typically has an oxidation number of +1 in compounds. For the entire H2PO3^- ion, the sum of the oxidation numbers must equal -1 to balance the charge of the ion. Therefore, the oxidation number of P would be +3 in this case.