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In 8 mg Magnesium is:

8(mg) / 24.31(mg/mmole) = 0.329 mmole Mg

(molar mass Mg being 24.31 mg/mmole)

In 0.329 mmole Mg is:

0.329(mmole) * 6.02*1023(atoms/mole)*10-3(mole/mmole) =

= 1.98*1020 atoms of Mg.

(Avogadro's Number being 6.02*1023)

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14y ago
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5mo ago

To find the number of atoms in 8 grams of magnesium, you need to first calculate the number of moles of magnesium using its molar mass (24.305 g/mol). Then, use Avogadro's number (6.022 x 10^23) to convert moles to atoms. This calculation would result in approximately 3.28 x 10^23 atoms of magnesium in 8 grams.

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Q: What number of atoms is present in 8 gm of magnesium?
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