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Balanced equation: 2Na(s) + O2(g) ---> Na2O(s)
moles Na = 115 g x 1 mol/23 g = 5 moles
moles Na2O possible = 1/2 x 5 moles = 2.5 moles (b/c the mole ratio of Na2O:Na is 1:2)
mass Na2O possible = 2.5 moles x 62 g/mole = 155 grams (assuming O2 is not limiting)

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8y ago
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8y ago

4Na(s) + O2(g) --> 2Na2O(s) 115g/23gmol-1=5mol Na. 2:1 ratio means 2.5mol product. Na2O=62g/mol. 2.5x62=155g Na2O.

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Q: What mass of sodium oxide could be made from 115grams of sodium?
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