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To find the molarity of the solution, we need to first calculate the number of moles of glucose in 154 grams. The molar mass of glucose is 180 g/mol. Dividing 154 g by 180 g/mol gives us 0.856 moles of glucose. Since the volume is 1 liter, the molarity is 0.856 M.
The chemical formula for glucose dissolving in water is: C6H12O6 +6O2 ---->6CO2 +6H2O.
The molar mass of glucose (C6H12O6) is 180.16 g/mol. To find the molarity, divide the mass of glucose by its molar mass and the volume of the solution in liters. Molarity = (32.8 g / 180.16 g/mol) / 1.0 L = 0.182 M.
The boiling point of water increases by 0.51 degrees Celsius, and the freezing point decreases by 1.86 degrees Celsius for a 1-molal solution of glucose in water. Since we have a 45-gram portion of glucose in 500 grams of water, we can calculate the molality and use it to determine the changes in the boiling and freezing points.
Glucose is a simple sugar with the chemical formula C6H12O6. It is a monosaccharide and a key source of energy for living organisms.
The solution with glucose (C6H12O6) would have the lowest freezing point. This is because the number of particles in the solution contributes to the lowering of the freezing point, and glucose, being a covalent compound, dissociates into more particles in solution compared to the other compounds given.
To find the molarity of the solution, we need to first calculate the number of moles of glucose in 154 grams. The molar mass of glucose is 180 g/mol. Dividing 154 g by 180 g/mol gives us 0.856 moles of glucose. Since the volume is 1 liter, the molarity is 0.856 M.
The pH of a solution of C6H12O6 (glucose) is neutral at pH 7 since it does not directly contribute to H+ ions in solution.
The chemical formula for glucose dissolving in water is: C6H12O6 +6O2 ---->6CO2 +6H2O.
The chemical formula for glucose is C6H12O6.
The molar mass of glucose (C6H12O6) is 180.16 g/mol. To find the molarity, divide the mass of glucose by its molar mass and the volume of the solution in liters. Molarity = (32.8 g / 180.16 g/mol) / 1.0 L = 0.182 M.
Glucose solution is a homogeneous mixture because it is composed of glucose dissolved in water, making it uniform throughout.
Because NaCl produces double no of particles(Na+ and Cl-) in solution as compare to Glucose (C6H12O6)
The boiling point of water increases by 0.51 degrees Celsius, and the freezing point decreases by 1.86 degrees Celsius for a 1-molal solution of glucose in water. Since we have a 45-gram portion of glucose in 500 grams of water, we can calculate the molality and use it to determine the changes in the boiling and freezing points.
The normal sugar is Sucrose, when it is dissolved in water it slowly decomposes to Glucose and Fructose. The reaction is catalised by acids (H+) like present in softdrinks.C12H22O11 + H2O --[H+]--> C6H12O6(Glucose) + C6H12O6(Fructose)
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The chemical compound for glucose is C6H12O6, representing its molecular formula.