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The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
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What is the volume of 10.9 mol of helium at STP?
The volume of 10.9 mol of helium at STP is 50 litres.
How much does 75.0 L of helium weigh?
The weight of 75.0 L of helium depends on the temperature and pressure at which it is measured. At standard temperature and pressure (STP), which is 0°C and 1 atmosphere, the molar mass of helium is 4.0 grams per mole. Using the ideal gas law, we can calculate the weight by multiplying the molar mass of helium by the number of moles, which is the volume divided by 22.4 L (molar volume at STP). However, if the temperature and pressure are not at STP, additional information is needed to determine the weight.
What would the volume of 28g of helium be at STP?
It would be 7 x 22.4 litre ie 156.8 litre.
Why does HE have a molar volume of 22.4dm3 at stp and ch3cl have a molar volume of 21.9dm3 at stp?
Because at STP, Chloroform is liquid and Helium is in gaseous state. When something is in a gaseous state, it occupies a larger space than the liquid. I thought however, that chloroform would occupy less than that
10mL of Helium equal to how much gram?
10 mL of helium at standard conditions (STP) would weigh approximately 0.0125 grams.
What is the volume of 10.9 mol of helium at STP?
The volume of 10.9 mol of helium at STP is 50 litres.
What is the answer to this conversion 0.0396 moles of helium into liters at STP?
The volume is 0.887 L.
What is the mass of 43.7 L of helium at STP?
The molar volume of gas at STP is 22.4 L/mol. Helium has a molar mass of 4.0 g/mol. Using the ideal gas law, we can calculate that the mass of 43.7 L of helium at STP is approximately 61.6 g.
How much does 75.0 L of helium weigh?
The weight of 75.0 L of helium depends on the temperature and pressure at which it is measured. At standard temperature and pressure (STP), which is 0°C and 1 atmosphere, the molar mass of helium is 4.0 grams per mole. Using the ideal gas law, we can calculate the weight by multiplying the molar mass of helium by the number of moles, which is the volume divided by 22.4 L (molar volume at STP). However, if the temperature and pressure are not at STP, additional information is needed to determine the weight.
What would the volume of 28g of helium be at STP?
It would be 7 x 22.4 litre ie 156.8 litre.
Why does HE have a molar volume of 22.4dm3 at stp and ch3cl have a molar volume of 21.9dm3 at stp?
Because at STP, Chloroform is liquid and Helium is in gaseous state. When something is in a gaseous state, it occupies a larger space than the liquid. I thought however, that chloroform would occupy less than that
What is the state of matter by helium?
Helium is a gas at STP.
What is the state of for helium?
Helium exists as a gas at STP
10mL of Helium equal to how much gram?
10 mL of helium at standard conditions (STP) would weigh approximately 0.0125 grams.
At STP 32 grams of O2 would occupy the same volume as?
At STP (standard temperature and pressure), 32 grams of O2 would occupy the same volume as 22.4 liters, which is the molar volume of any ideal gas at STP.
What is the nature of helium?
gas at STP
What would be the volume of 6.00 g of helium gas at STP?
If these atoms are loose unities, not bonded in a molecule, it would be about 22 dm3 at 0oC and standard pressure (STP). If the atoms would have formed gas molecules, e.g. CO2 or SF6, the answer would be different, because 6.02 x 1023 molecules always take in a volume of about 22 dm3 at STP. But with CO2 you would have then 18 x 1023 atoms because there are 3 atoms in one molecule.
