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What is the structure of alkane with 9 carbons all tertiary?
Jessicah5377
I'm pretty sure this is impossible.
A tertiary carbon is bonded to three other carbons. Counting each of these 3 as one-half of a carbon-carbon bond (the other half coming from the other carbon), that means that if there are 9 carbons, there must be 27 half bonds in the molecule, which works out to thirteen carbon-carbon bonds plus half a bond left over.
Since you can't have half a bond in a real compound, it's not possible to arrange nine carbons so that each one is bonded to three others.
You can do it with 8, in which case you get cubane.
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Uh you shouldn't label this as impossible. I reckon its COMPLETELY POSSIBLE!
For example: look at this:
H H H H H H H H H
| | | | | | | | |
H-C-C-C-C-C-C-C-C-C-H
| | | | | | | | |
H H H H H H H H H
This is Nonane (C9H20).
I'm not too sure if this is right, but so far it looks pretty good-and makes sense. So that puts a whole in your answer up there =P
*OMGG! see those vertical hydrogen-carbon bonds (or lines in between the Hydrogens and Carbons) ther actually supposed to connect the 9 carbons to the the 2 hydrogen atoms above and under them. Sorry, i had it perfect before, but when i save it screws up. Hope this helps...
**Ink and Paper**
---Yo i think my answer is wrong, but i ain't gonna delete it coz it took me time---
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∙ 12y ago
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