1999
The formula for calculating residence time is: Residence time = Volume of the system / Flow rate of the system. This formula helps in determining the average amount of time a substance will spend in a system or a reactor.
The address of the Meridian District is: 1326 W Cherry Ln, Meridian, 83642 1516
Radioactive decay can be expressed by the following equation:N(t) = N0 e-ktwhere k is the decay constant = ln 2 / t0.5 (t0.5 is the half-life in years)k = ln 2/5570 yrs = 0.0001244So our equation is :N(t) = N0e-0.0001244tYou know that only 41% of the initial C-14 remains therefore N(t) = 0.41*N00.41N0 = N0e-0.0001244t (now rearrange & solve t to find the age)0.41N0/N0 = e-0.0001244tln (0.41) = ln (e-0.0001244t) (take the natural log (ln) of both sides)-0.8915 = -0.0001244*tt = 7167 years
To calculate species diversity using the Shannon-Weiner index, you need to sum the multiplication of the proportion of each species (pi) by the natural logarithm of the proportion of each species (ln(pi)) for all species in the community. The Shannon-Weiner index formula is H = - Σ (pi * ln(pi)). Species evenness can be calculated by dividing the Shannon-Weiner index by the maximum possible value of the index, which is ln(total number of species). Higher evenness values indicate a more even distribution of species in the community.
codominance
LM = 4 in LN = ? Find LN. Round the answer to the nearest tenth.
4.60
ln/mkl;m;/lm;lok
A basic logarithmic equation would be of the form y = a + b*ln(x)
y = a + b*log(x) or y = a + b*ln(x) where a and b are constants.
If L1=1 and L2=2, we would just get the Fibonacci sequence. Recall that the Fibonacci sequence is recursive and given by: f(0)=1, f(1)=1, and f(n)=f(n-1)+f(n-2) for integer n>1. Thus, we have f(2)=f(0)+f(1)=1+1=2. If L1=1 and L2=2 then we would have L1=f(1) and L2=f(2). Since the Lucas numbers are generated recursively just like the Fibonacci numbers, i.e. Ln=Ln-1+Ln-2 for n>2, we would have L3=L1+L2=f(1)+f(2)=f(3), L4=f(4), etc. You can use complete induction to show this for all n: As we have already said, if L1=1 and L2=2, then we have L1=f(1) and L2=f(2). We now proceed to induction. Suppose for some m greater than or equal to 2 we have Ln=f(n) for n less than or equal to m. Then for m+1 we have, by definition, Lm+1=Lm+Lm-1. By the induction hypothesis, Lm+Lm-1=f(m)+f(m-1), but this is just f(m+1) by the definition of Fibonnaci numbers, i.e. Lm+1=f(m+1). So it follows that Ln=f(n) for all n if we let L1=1 and L2=2.
Ln 4 + 3Ln x = 5Ln 2 Ln 4 + Ln x3= Ln 25 = Ln 32 Ln x3= Ln 32 - Ln 4 = Ln (32/4) = Ln 8= Ln 2
18
ln(ln)
I think you are thinking "natural logarithm" which is ln (lowercase L, not I). If you have taken calculus you learn about logarithm and its relationship with exponents
Take the natural logarithm (ln) of both sides of the equation to cancel the exponent (e). For example, ify=Aexlog transform both sides and apply the rules of logarithms:ln(y)=ln(Aex)ln(y)=ln(A)+ln(ex)ln(y)=ln(A)+xrearrange in terms of x:x=ln(y)-ln(A), or more simplyx=ln(y/A)