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When strontium nitrate and ammonium carbonate react, they form strontium carbonate, ammonium nitrate, and water. This reaction is a double displacement reaction where the cations and anions in the compounds switch partners to form new compounds.
When strontium nitrate (Sr(NO3)2) is added to water, it dissolves into its ions, releasing strontium ions (Sr2+) and nitrate ions (NO3-) into solution. This process is a physical change, not a chemical reaction, as no new substances are formed.
When silver nitrate and strontium iodide react, a double displacement reaction occurs. Silver iodide and strontium nitrate are formed as products. Silver iodide is a yellow precipitate while strontium nitrate remains in solution.
The molecular equation for the reaction between potassium carbonate (K2CO3) and strontium nitrate (Sr(NO3)2) is: 2K2CO3 + Sr(NO3)2 → 2KNO3 + SrCO3
The product of strontium bromide and silver nitrate is strontium nitrate and silver bromide. This is because there is a double displacement reaction between the two compounds where the cations and anions switch partners.
by the reaction of lead nitrate with potassium chromate or potassium dichromate
A double displacement reaction will occur, forming solid lead(II) chromate and soluble potassium nitrate. Lead(II) chromate is a yellow precipitate, while potassium nitrate remains in solution.
The reaction between magnesium nitrate and potassium chromate is a chemical reaction, as it involves the formation of new substances. The chemical equation for the reaction is: 2 Mg(NO3)2 + K2CrO4 -> MgCrO4 + 2 KNO3
The number of moles of silver chromate formed will depend on the stoichiometry of the reaction between silver nitrate and potassium chromate. You need to know the balanced chemical equation, as well as the exact volumes and concentrations of the silver nitrate and potassium chromate solutions to calculate the number of moles of silver chromate formed.
When potassium chromate is treated with barium nitrate, a double displacement reaction occurs. Barium chromate and potassium nitrate are formed as products. A yellow precipitate of barium chromate is observed in the reaction mixture.
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium chromate (K2CrO4) is: Ag+ + 2NO3- + 2K+ + CrO42- -> Ag2CrO4(s) + 2KNO3 This reaction forms silver chromate (Ag2CrO4) as a solid precipitate, with potassium nitrate (KNO3) remaining in solution.
The balanced formula for strontium nitrate (Sr(NO3)2) reacting with potassium phosphate (K3PO4) is 3Sr(NO3)2 + 2K3PO4 -> Sr3(PO4)2 + 6KNO3.
When aluminum is mixed with potassium nitrate, a reaction occurs where aluminum displaces potassium to form aluminum nitrate and potassium nitride. The reaction is exothermic, producing heat and light.
These substances doesn't react.
The reaction between silver nitrate and potassium iodide forms silver iodide precipitate and potassium nitrate. This reaction is a double displacement reaction where the silver ions from silver nitrate switch places with the potassium ions in potassium iodide.
When silver nitrate and strontium iodide react, a double displacement reaction occurs. Silver iodide and strontium nitrate are formed as products. Silver iodide is a yellow precipitate while strontium nitrate remains in solution.
The reaction equation for potassium nitrate (KNO3) with water (H2O) is: KNO3 (s) + H2O (l) -> K+ (aq) + NO3- (aq) + H2O. This reaction is a dissolution reaction, where the solid potassium nitrate dissolves in water to form aqueous potassium ions, nitrate ions, and water molecules.