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The reaction for benzoic acid and methyl amine produces benzamide. The equation is C6H5COOH + CH3NH2 ---> C6H5CONHCH3 + H2O.

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10y ago
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6mo ago

The reaction between benzoic acid and N-methylethanamine would result in the formation of N-methylbenzamide and water. This reaction is an example of amide formation through condensation.

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15y ago

Methyl benzoate. C6H5COOCH3

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13y ago

Benzoylmethylethylamide.

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Q: What is the product of benzoic acid plus n-methylethanamine?
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The chemical equation you have written shows the reaction between hydrochloric acid (HCl) and sodium benzoate (C6H5COONa). This reaction results in the formation of benzoic acid (C6H5COOH) as a solid and sodium chloride (NaCl).


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The correct Ka value for benzoic acid is 6.3 x 10^-5. This can be calculated using the equation Ka = [H+][C6H5COO-] / [C6H5COOH]. Plugging in the values given ([H+] = 3.55 x 10^-3 M, [C6H5COOH] = 0.200 M) gives Ka = (3.55 x 10^-3)(3.55 x 10^-3) / (0.200) = 6.3 x 10^-5.


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