Wiki User
∙ 11y agoNo probability. Neither parent has an "A" for the child to inherit to make an "AB".
Wiki User
∙ 11y agoThe woman would have genotype AO (IAIA) for blood type A, the man would have genotype BO (IBIB) for blood type B, and their child with blood type O would have genotype OO (ii). The child inherited one O allele from each parent.
If an AC genotype man and an AS genotype woman marry, each of their children has a 25% chance of being born with a sickle cell disease (SS genotype), a 50% chance of being a carrier like their parents (AS genotype), and a 25% chance of having a normal genotype (AA).
The man's genotype is PP, and the woman's genotype is pp. Their children will all be Pp carriers of the perfect pitch trait. The probability that any of their children will NOT have perfect pitch is 0%, as all will inherit at least one copy of the perfect pitch trait.
The genotype of a man with sickle cell trait is HbAS, which means he has inherited one normal hemoglobin gene (HbA) and one sickle hemoglobin gene (HbS).
the genotype for a male is XY thank you, Allyson
If the woman is homozygous for A-negative blood type (genotype aa) and the man is AB-negative (genotype AB), they can only pass on an A allele and a B allele to their child. Therefore, the child will have blood type AB, not B-negative.
Dd
The woman would have genotype AO (IAIA) for blood type A, the man would have genotype BO (IBIB) for blood type B, and their child with blood type O would have genotype OO (ii). The child inherited one O allele from each parent.
[object Object]
Make a punnet square with the mother above, her genotype would be: X^B X^b, and the father to the left whose genotype is X^b Y.The probability of having a colorblind CHILD is 50%. The probability of them having a SON is 50%. Since we are asked what the probability of their SON being colorblind, it is 50% as well. The reason is because the chance of having a colorblind son, among sons only, (according to the punnet square) is 50%.
Yes. The woman has a genotype of BO. Each child is a "reset" of the 50/50 probability of being group O or group B.
If an AC genotype man and an AS genotype woman marry, each of their children has a 25% chance of being born with a sickle cell disease (SS genotype), a 50% chance of being a carrier like their parents (AS genotype), and a 25% chance of having a normal genotype (AA).
No. In order to have an O child, both parents must have a genotype of at least iAi or iBi. If you're AB blood type, then the genotype is iAiB has no space for O gene to come about.
This question is worded weird, because if someone had a dominant phenotype, as in Brown eyes dominant, than they would be BB or Bb. The exact genotype would need to have a key to what one of their parents' genotype was. Example: If a man with brown eyes (dominant) had a mom with blue eyes (recessive) then what would the man's genotype be? the answer would be Bb because that means that the man's dad would have BB and mom would be bb and when using punnent square, his genotype is Bb (only possible genotype is Bb)
sexual intercourse(sex)
Of course not are you crazy you always have to have a wife with you
Yes.