The oxidation state of N in NH4+ is -3. Nitrogen typically has an oxidation state of -3 when it is in the ammonium ion (NH4+).
Ammonia (NH3) contains nitrogen in its lowest oxidation state, which is -3.
The oxidation state of a diamine molecule would typically be 0, as each nitrogen atom contributes one electron to form the N-N bond. However, the oxidation state can vary depending on the specific compound and its chemical environment.
Generally third A group elements in the periodic table exhibit +3 oxidation state but Boron exhibit negative oxidation state also . The stable oxidation state of Tl is +1. It exhibit +3 also but +1 is more stable than +3. RGUKT IIIT NUZVID N091528
It is simply known as rubidium nitrite.
N has +3 state on it.Each H have -1 state.
I think +3 oxidation state
The oxidation state of N in NH4+ is -3. Nitrogen typically has an oxidation state of -3 when it is in the ammonium ion (NH4+).
The oxidation state of N in HNO2 is +3. This is because, in a neutral molecule like HNO2, the sum of the oxidation states of all atoms must equal zero. Since the oxidation state of H is +1 and O is -2, the oxidation state of N in HNO2 must be +3 to balance it out.
The oxidation state of nitrogen (N) in NH4+ is -3. Nitrogen usually has a -3 oxidation state in ammonium ion (NH4+) as hydrogen is typically considered to have +1 oxidation state and there are four hydrogen atoms bonded to nitrogen in NH4+.
The oxidation number of N in NO2 is +4. Each oxygen atom in NO2 has an oxidation state of -2, so the oxidation state of nitrogen can be calculated as follows: 2*(-2) + x = 0, where x is the oxidation state of N. Solving for x gives us x = +4.
The oxidation state of nitrogen (N) in nitric acid (HNO3) is +5. This is because hydrogen has an oxidation state of +1 in compounds, and oxygen usually has an oxidation state of -2. Since there are three oxygen atoms with a total oxidation state of -6 and one hydrogen atom with an oxidation state of +1, the nitrogen atom must have an oxidation state of +5 to balance out the charges and make the molecule neutral.
Zero.for an element in the free state oxidation no is always zero.
Ammonia (NH3) contains nitrogen in its lowest oxidation state, which is -3.
The oxidation number of nitrogen (N) in Ca3N2 is -3. This is because calcium (Ca) has an oxidation state of +2, and the overall compound is neutral, so the oxidation states must balance out to zero. Since there are three Ca atoms with an oxidation state of +2, the nitrogen atoms must have an oxidation state of -3 to balance the charges.
The oxidation state of a diamine molecule would typically be 0, as each nitrogen atom contributes one electron to form the N-N bond. However, the oxidation state can vary depending on the specific compound and its chemical environment.
Oxidation State is -1. This is because N= 5 AND O=-2 5+3*(-2)=-1