C = +2 oxidation state O = -2 oxidation state
The oxidation state of oxygen in H2O2 (hydrogen peroxide) is -1. Each hydrogen atom has an oxidation state of +1, so the total oxidation state must add up to zero in a neutral molecule.
S = +4 oxidation state O = -2 oxidation state
The oxidation state is +3.
The oxidation state of F in HOF (hydrogen monofluoride) is -1. Hydrogen is typically assigned an oxidation state of +1, leaving the fluorine with an oxidation state of -1.
+4 oxidation state
The oxidation state of carbon (C) in CO2 is +4. Each oxygen atom in CO2 has an oxidation state of -2, so for the overall molecule to be neutral, carbon must have an oxidation state of +4.
The oxidation number of carbon (C) depends on the compound it is in. In most organic compounds, carbon has an oxidation number of +4, +2, 0, or -4.
C = +2 oxidation state O = -2 oxidation state
In COH2, the oxidation state of C is +2, the oxidation state of O is -2, and the oxidation state of H is +1.
The oxidation state of sodium (Na) in Na2C2O4 is +1 because it is an alkali metal. The oxidation state of carbon (C) in C2O4^2- (oxalate ion) is +3.
The oxidation state of cobalt in CoCO3 is +2. It forms a ionic compound where cobalt exists as Co^2+ ion.
In H2C2O4 (oxalic acid), the oxidation state of hydrogen (H) is +1, the oxidation state of carbon (C) is +3, and the oxidation state of oxygen (O) is -2.
Zinc is in oxidation state +2 and oxygen in oxidation state -2. Zinc Oxide itself has not net charge/oxidation state.
The oxidation number of Ca in CaC2O4 is +2 because Ca, a group 2 element, typically has a +2 oxidation state in compounds. The oxidation number of C in C2O4 is +3 because the overall charge of the oxalate ion is -2, and there are two C atoms, each with an oxidation state of +3 to balance the charge.
The oxidation number for C in NH2CONH2 is +2. This is because each hydrogen has an oxidation number of +1, and oxygen has an oxidation number of -2. By assigning hydrogen and oxygen their usual oxidation numbers, we can determine that the nitrogen atoms in NH2CONH2 have an oxidation state of -3, and since each nitrogen atom contributes three electrons to the carbon atom, the overall oxidation state of carbon is +2.
Here O S of C is -4As,let us take O S of C as xSo, O S of H is +1In CH4 as it is stable so the eq. isx+4(+1)=0or, x = - 4