The oxidation number is + for C and -2 for O.
The most common oxidation state for selenium is -2, but it can also exist in oxidation states of +4 and +6 depending on the compound it is in.
In the reaction, aluminum in Al2(SO4)3 has an oxidation number of +3. Hydrogen in H2 has an oxidation number of 0.
No, the oxidation number of oxygen in ozone (O3) is -2/3, while in oxygen (O2) it is 0. In ozone, one oxygen atom has an oxidation number of -1 and the other two have an oxidation number of 0, resulting in an average oxidation number of -2/3.
+2 for Mg -2 for O
The oxidation number for oxygen (O) in KO2 is -1. Since the overall charge of the compound is 0, the oxidation number of potassium (K) is +1.
The oxidation number for O in K2O is -2. Oxygen typically has an oxidation number of -2 in most compounds. Since there are two oxygen atoms in K2O, the total oxidation number contributed by the oxygen atoms is -4.
In KO2, O has an oxidation number of -1, K has an oxidation number of +1. In CO2, O has an oxidation number of -2, C has an oxidation number of +4. In K2CO3, O has an oxidation number of -2, C has an oxidation number of +4, and K has an oxidation number of +1. In the given reaction, the oxidation numbers for each atom remain the same as in their individual compounds.
The oxidation state of Na in Na2O2 is +1, as each Na atom carries a +1 charge while the O atoms carry a -1 charge. In KO2, the oxidation state of K is +1, similar to Na2O2, as each K atom carries a +1 charge while the O atoms carry a -1/2 charge.
The oxidation number for H is +1, and the oxidation number for O is -1.
In N2O5, the oxidation number of N (nitrogen) is +5 and the oxidation number of O (oxygen) is -2.
The oxidation number of C in CH3OH is -2, the H atoms have an oxidation number of +1 each, and the O atom has an oxidation number of -2.
The oxidation number of O in any elemental form (e.g. O2, O3) is zero. Typically in chemical compounds the oxidation number of O is -2 (oxide ion)
The oxidation number of oxygen (O) in most compounds, including sulfate (SO4), is typically -2. In Na2SO4, sodium (Na) has an oxidation number of +1. To calculate the oxidation number of oxygen in the compound, you would use the equation: 2(oxidation number of Na) + oxidation number of S + 4(oxidation number of O) = 0. By plugging in the known values, you can solve for the oxidation number of oxygen in Na2SO4.
The oxidation number of Na in NaNO3 is +1, the oxidation number of N in NO3 is +5, and the oxidation number of O in NO3 is -2.
The oxidation number of oxygen (O) in O2^2- is -1. Each oxygen atom has an oxidation number of -1, and since there are two oxygen atoms in the ion, the total charge of -2 is balanced.
Rb has an oxidation number of +1, Cl has an oxidation number of -1, and O has an oxidation number of -2 based on common rules. Therefore, the oxidation number for RbClO would be +1 for Rb, -1 for Cl, and -2 for O.