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54,9 mmol of sulfur dioxide is equivalent to 3,517 g.

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Q: What is the number of grams in 54.9 mmol SO2?
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How many moles of SO2 is present in 0.45 grams of sulfur dioxide?

To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.


How many grams are in 0.400 mole of SO2?

To calculate the number of grams in 0.400 moles of SO2, you first need to determine the molar mass of SO2, which is approximately 64.07 g/mol. Then, you multiply the molar mass by the number of moles: 64.07 g/mol x 0.400 mol = 25.63 grams of SO2.


How many gram-moles in 320 grams of SO2?

To determine the number of gram-moles in 320 grams of SO2, you first need to find the molar mass of SO2, which is 64.07 g/mol. Then you divide the given mass (320 g) by the molar mass to get the number of moles. Therefore, 320 grams of SO2 is equivalent to 5 moles.


The number of grams in 2.65 mol of So2 is 2.65?

To find the number of grams in 2.65 mol of SO2, you need to multiply the molar mass of SO2 by the number of moles given. The molar mass of SO2 is approximately 64.07 g/mol. So, 2.65 mol of SO2 would be equivalent to 2.65 mol * 64.07 g/mol = 169.48 g.


How many grams are in 0.75 moles of SO2?

To convert moles to grams, you need to use the molar mass of the compound. The molar mass of SO2 is approximately 64.07 g/mol. Multiplying the number of moles by the molar mass gives: 0.75 moles x 64.07 g/mol = 48.0525 grams of SO2.


How many moles are present in 128 grams of sulphur dioxide?

To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.


What is the total mass in grams of 0.75 mole of SO2?

To find the total mass of 0.75 moles of SO2, you need to calculate the molar mass of SO2 and then multiply it by the number of moles. The molar mass of SO2 is approximately 64.06 g/mol. Therefore, the total mass of 0.75 moles of SO2 is 0.75 mol * 64.06 g/mol = 48.045 grams.


How many grams of sulfur must be burned to give 100.0 g of SO2?

To calculate the number of grams of sulfur burned to produce 100.0 g of SO2, we first need to find the molar mass of SO2. The molar mass of SO2 is 64.1 g/mol. Since there is one sulfur atom in each molecule of SO2, the molar mass of sulfur is 32.1 g/mol. Therefore, 32.1 grams of sulfur must be burned to produce 100.0 g of SO2.


What is the total mass and grams of 0.75 mole of SO2?

The molar mass of SO2 is approximately 64.07 g/mol. To find the mass of 0.75 moles of SO2, you would multiply the number of moles by the molar mass: 0.75 moles x 64.07 g/mol = 48.05 grams Therefore, the total mass of 0.75 moles of SO2 is 48.05 grams.


How many moles of SO2 are present in 250.0 g?

Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.


What is the volume of 72 grams of SO2?

To find the volume of 72 grams of SO2, you need to convert the mass to moles using the molar mass of SO2 (64.06 g/mol). Then, you can use the ideal gas law to calculate the volume at a given temperature and pressure.


How many molecules of sulfur dioxide are present in 72 g of the substance?

To determine the number of molecules of sulfur dioxide in 72 g, you need to convert the mass of sulfur dioxide (in grams) to moles using the molar mass of sulfur dioxide. Then use Avogadro's number (6.022 x 10^23 molecules/mol) to convert from moles to molecules.