A nuclear equation for the decay of technetium-99m is: Tc-99m -> Tc-99 + e- + v Here, Tc-99m decays to Tc-99 by emitting an electron and an antineutrino in the process.
beryllium 7 accepts a beta particle to convert to lithium 7 4Be7 + -1e0 = 3Li7
The nuclear decay equation for carbon-11 is: [ _{6}^{11}C \rightarrow {7}^{11}N + e^{+} + \nu{e} ] where ({6}^{11}C) is the carbon-11 nucleus, ({7}^{11}N) is the nitrogen-11 nucleus, (e^{+}) is a positron (positive electron), and ( \nu_{e} ) is an electron neutrino.
Yes, beryllium has multiple isotopes, with the most common being beryllium-9. Other isotopes of beryllium include beryllium-7 and beryllium-8.
If oxygen-16 was to undergo positron emission (beta plus decay), a proton in its nucleus would transform into a neutron (mediated by the weak force). The oxygen-16 would become nitrogen-16, and we'd see a positron and a neutrino appear. The equation might look like this: 816O => 716N + e+ + ve It is easy to write a balanced nuclear equation for any nuclide undergoing positron emission. Note the subscript numerals at the beginning of each element. That's the atomic number of that element. The superscript numerals are the atomic mass of the nuclide. When beta plus decay occurs, nuclear transformation takes place. The atomic number of the element goes down by one, and one element becomes another element. The subscripted numerals will reflect that decrease of one, and the atomic mass (the superscripted numerals) will remain the same. Note the last two factors in the equation, as they are the positron and the neutrino, respectively. That's the long and short of the beta plus decay of O-16, as asked. We'll add, however, that oxygen-16 is a stable isotope of oxygen. It does not undergo beta decay, but for the sake of argument, it did here. And with the results shown. By the way, it is oxygen-15 that is the radioactive isotope of oxygen that will undergo beta plus decay. You'll find links below for more information.
A nuclear equation for the decay of technetium-99m is: Tc-99m -> Tc-99 + e- + v Here, Tc-99m decays to Tc-99 by emitting an electron and an antineutrino in the process.
beryllium 7 accepts a beta particle to convert to lithium 7 4Be7 + -1e0 = 3Li7
The nuclear decay equation for carbon-11 is: [ _{6}^{11}C \rightarrow {7}^{11}N + e^{+} + \nu{e} ] where ({6}^{11}C) is the carbon-11 nucleus, ({7}^{11}N) is the nitrogen-11 nucleus, (e^{+}) is a positron (positive electron), and ( \nu_{e} ) is an electron neutrino.
A transmutation reaction is represented by an equation that shows the transformation of one element into another through nuclear processes, such as radioactive decay or nuclear bombardment. An example of a transmutation reaction is: [ ^{14}{7}N + ^{4}{2}He \rightarrow ^{17}{8}O + ^{1}{1}H ]
The nuclear charge of an element is equal to its atomic number. Therefore, the nuclear charge of the elements you listed are: lithium (3), beryllium (4), carbon (6), nitrogen (7), fluorine (9), and neon (10).
Natural beryllium isotopes are: Be-7, Be-9, Be-10.
Walton T. Boyer has written: 'A spectrometer for study of neutron activation of beryllium-7 as a function of energy' -- subject(s): Nuclear physics
Yes, beryllium has multiple isotopes, with the most common being beryllium-9. Other isotopes of beryllium include beryllium-7 and beryllium-8.
Equation 7 is not an equation and so cannot have a slope.
If oxygen-16 was to undergo positron emission (beta plus decay), a proton in its nucleus would transform into a neutron (mediated by the weak force). The oxygen-16 would become nitrogen-16, and we'd see a positron and a neutrino appear. The equation might look like this: 816O => 716N + e+ + ve It is easy to write a balanced nuclear equation for any nuclide undergoing positron emission. Note the subscript numerals at the beginning of each element. That's the atomic number of that element. The superscript numerals are the atomic mass of the nuclide. When beta plus decay occurs, nuclear transformation takes place. The atomic number of the element goes down by one, and one element becomes another element. The subscripted numerals will reflect that decrease of one, and the atomic mass (the superscripted numerals) will remain the same. Note the last two factors in the equation, as they are the positron and the neutrino, respectively. That's the long and short of the beta plus decay of O-16, as asked. We'll add, however, that oxygen-16 is a stable isotope of oxygen. It does not undergo beta decay, but for the sake of argument, it did here. And with the results shown. By the way, it is oxygen-15 that is the radioactive isotope of oxygen that will undergo beta plus decay. You'll find links below for more information.
The chemical formula for beryllium nitride is Be3N2. It consists of three beryllium atoms and two nitrogen atoms.
It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15