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The nuclear decay equation for beryllium-7 is: Be-7 -> Li-7 + e⁻ + νe This shows that beryllium-7 decays into lithium-7, an electron, and an electron antineutrino.

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Q: What is the nuclear decay equation for beryllium 7?
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What is a nuclear equation for technetium decay?

A nuclear equation for the decay of technetium-99m is: Tc-99m -> Tc-99 + e- + v Here, Tc-99m decays to Tc-99 by emitting an electron and an antineutrino in the process.


What is the nuclear reaction for beryllium-7 into lithium-7?

beryllium 7 accepts a beta particle to convert to lithium 7 4Be7 + -1e0 = 3Li7


What is the nuclear decay equation for carbon 11?

The nuclear decay equation for carbon-11 is: [ _{6}^{11}C \rightarrow {7}^{11}N + e^{+} + \nu{e} ] where ({6}^{11}C) is the carbon-11 nucleus, ({7}^{11}N) is the nitrogen-11 nucleus, (e^{+}) is a positron (positive electron), and ( \nu_{e} ) is an electron neutrino.


Does beryllium have a isotope?

Yes, beryllium has multiple isotopes, with the most common being beryllium-9. Other isotopes of beryllium include beryllium-7 and beryllium-8.


How do you write a balanced nuclear equation for the positron emission of nitrogen-13?

If oxygen-16 was to undergo positron emission (beta plus decay), a proton in its nucleus would transform into a neutron (mediated by the weak force). The oxygen-16 would become nitrogen-16, and we'd see a positron and a neutrino appear. The equation might look like this: 816O => 716N + e+ + ve It is easy to write a balanced nuclear equation for any nuclide undergoing positron emission. Note the subscript numerals at the beginning of each element. That's the atomic number of that element. The superscript numerals are the atomic mass of the nuclide. When beta plus decay occurs, nuclear transformation takes place. The atomic number of the element goes down by one, and one element becomes another element. The subscripted numerals will reflect that decrease of one, and the atomic mass (the superscripted numerals) will remain the same. Note the last two factors in the equation, as they are the positron and the neutrino, respectively. That's the long and short of the beta plus decay of O-16, as asked. We'll add, however, that oxygen-16 is a stable isotope of oxygen. It does not undergo beta decay, but for the sake of argument, it did here. And with the results shown. By the way, it is oxygen-15 that is the radioactive isotope of oxygen that will undergo beta plus decay. You'll find links below for more information.

Related questions

What is a nuclear equation for technetium decay?

A nuclear equation for the decay of technetium-99m is: Tc-99m -> Tc-99 + e- + v Here, Tc-99m decays to Tc-99 by emitting an electron and an antineutrino in the process.


What is the nuclear reaction for beryllium-7 into lithium-7?

beryllium 7 accepts a beta particle to convert to lithium 7 4Be7 + -1e0 = 3Li7


What is the nuclear decay equation for carbon 11?

The nuclear decay equation for carbon-11 is: [ _{6}^{11}C \rightarrow {7}^{11}N + e^{+} + \nu{e} ] where ({6}^{11}C) is the carbon-11 nucleus, ({7}^{11}N) is the nitrogen-11 nucleus, (e^{+}) is a positron (positive electron), and ( \nu_{e} ) is an electron neutrino.


Which equation represents a transmutation reaction?

A transmutation reaction is represented by an equation that shows the transformation of one element into another through nuclear processes, such as radioactive decay or nuclear bombardment. An example of a transmutation reaction is: [ ^{14}{7}N + ^{4}{2}He \rightarrow ^{17}{8}O + ^{1}{1}H ]


What is the nuclear charge of lithium beryllium carbon nitrogen fluorine and neon?

The nuclear charge of an element is equal to its atomic number. Therefore, the nuclear charge of the elements you listed are: lithium (3), beryllium (4), carbon (6), nitrogen (7), fluorine (9), and neon (10).


What are some of beryllium isotopes?

Natural beryllium isotopes are: Be-7, Be-9, Be-10.


What has the author Walton T Boyer written?

Walton T. Boyer has written: 'A spectrometer for study of neutron activation of beryllium-7 as a function of energy' -- subject(s): Nuclear physics


Does beryllium have a isotope?

Yes, beryllium has multiple isotopes, with the most common being beryllium-9. Other isotopes of beryllium include beryllium-7 and beryllium-8.


What is the slope for the equation 7?

Equation 7 is not an equation and so cannot have a slope.


How do you write a balanced nuclear equation for the positron emission of nitrogen-13?

If oxygen-16 was to undergo positron emission (beta plus decay), a proton in its nucleus would transform into a neutron (mediated by the weak force). The oxygen-16 would become nitrogen-16, and we'd see a positron and a neutrino appear. The equation might look like this: 816O => 716N + e+ + ve It is easy to write a balanced nuclear equation for any nuclide undergoing positron emission. Note the subscript numerals at the beginning of each element. That's the atomic number of that element. The superscript numerals are the atomic mass of the nuclide. When beta plus decay occurs, nuclear transformation takes place. The atomic number of the element goes down by one, and one element becomes another element. The subscripted numerals will reflect that decrease of one, and the atomic mass (the superscripted numerals) will remain the same. Note the last two factors in the equation, as they are the positron and the neutrino, respectively. That's the long and short of the beta plus decay of O-16, as asked. We'll add, however, that oxygen-16 is a stable isotope of oxygen. It does not undergo beta decay, but for the sake of argument, it did here. And with the results shown. By the way, it is oxygen-15 that is the radioactive isotope of oxygen that will undergo beta plus decay. You'll find links below for more information.


What is the formula beryllium Nitride?

The chemical formula for beryllium nitride is Be3N2. It consists of three beryllium atoms and two nitrogen atoms.


What is triple the quotient of a number and seven is fifteen?

It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15