6.02 ten to the power of 23
The molar mass of CO2 is approximately 44.01 g/mol. Therefore, half a mole of CO2 would have a mass of around 22.0 g.
atomic weight of carbon dioxide is 2 * 16 + 12 = 44 1 kg = 1000 g 1 kg of co2 has 1000/44 = 22.7 moles yeh i think that's wrong lol isn't it 3.37E25?
When 1 mole of C8H18 is burned, it forms 8 moles of CO2. Therefore, when 451 moles of C8H18 is burned, it will form 8 * 451 = 3608 moles of CO2.
To calculate the percent of CaCO3 in the limestone, first determine the molar mass of CaCO3 (100.09 g/mol). Next, calculate the moles of CO2 produced from the reaction (0.44 g CO2 / 44.01 g/mol). Since 1 mole of CaCO3 produces 1 mole of CO2, the moles of CaCO3 in the limestone can be calculated. Finally, determine the mass percent of CaCO3 in the limestone (mass of CaCO3 / total mass of limestone).
The molecular weight of carbon dioxide (CO2) is about 44 grams per mole. This means that one mole of CO2 weighs 44 grams.
6.02 ten to the power of 23
The molar mass of CO2 is approximately 44.01 g/mol. Therefore, half a mole of CO2 would have a mass of around 22.0 g.
In one mole of CO2, there is one mole of carbon (C). So if you have 1 mole of CO2, you have 1 mole of carbon.
Sodium Bicarbonate come from absorption of CO2 into NaOH Total reaction is 2NaOH + CO2 -> NaHCO3 + H2O Each mole of NaHCO3 come from absorption of 1 mole CO2 Molecular weight of NaHCO3 is 84 g/mol and CO2 is 44 g/mol It is that 84 g of NaHCO3 had 44 g of CO2 By weight ratio it is 52% CO2 in Sodium Bicarbonate.
In CO2, there is 1 carbon atom for every 1 molecule of CO2. Therefore, the number of moles of C in 0.00831 moles of CO2 would be 0.00831 moles.
Assuming you mean gaseous CO2. You can roughly approximate by PV=nRT, where P and T are ambient pressure and temperature and V is the volume of the Lorry. Solve for # of moles, n. (n=PV/(RT)) For weight of CO2, each mole = atomic weight of Carbon plus 2x atomic weight of Oxygen. (44.01 grams / mole)
atomic weight of carbon dioxide is 2 * 16 + 12 = 44 1 kg = 1000 g 1 kg of co2 has 1000/44 = 22.7 moles yeh i think that's wrong lol isn't it 3.37E25?
No, a mole of uranium will have a different number of particles compared to a mole of CO2. This is because the mole is a unit of measurement representing Avogadro's number of particles, which is 6.022 x 10^23 entities. The molar mass of uranium and CO2 are different, resulting in a different number of particles in a mole of each substance.
When 1 mole of C8H18 is burned, it forms 8 moles of CO2. Therefore, when 451 moles of C8H18 is burned, it will form 8 * 451 = 3608 moles of CO2.
To calculate the percent of CaCO3 in the limestone, first determine the molar mass of CaCO3 (100.09 g/mol). Next, calculate the moles of CO2 produced from the reaction (0.44 g CO2 / 44.01 g/mol). Since 1 mole of CaCO3 produces 1 mole of CO2, the moles of CaCO3 in the limestone can be calculated. Finally, determine the mass percent of CaCO3 in the limestone (mass of CaCO3 / total mass of limestone).
Yes, both carbon dioxide and oxygen have mass. Carbon dioxide has a molecular weight of approximately 44 grams per mole, while oxygen has a molecular weight of approximately 32 grams per mole.