Since KHP is an unknown (name for a) chemical compound the molarity can not be calculated by lack of data.
The molar mass (m) of KHP ANDthe number (n) of H+ per mol KHP (maybe 1 when monoprotic?) is necessary for calculation, according to this formula:
(M*V)NaOH = (n*mass/m)KHP
so:
[OH-] (mol.L-1) * 0.02850 (L NaOH sol'n) = n (mol H+.mol-1 KHP) * 0.7154 (g KHP) / m (g.mol-1 KHP)
1.3g
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
The molarity is 6.
To determine CaO and MgO in cement using EDTA titration, you would first make a solution of the cement sample, then add an appropriate buffer solution and a few drops of a suitable indicator. Next, you'd titrate the solution with EDTA until the color changes indicating the endpoint. By knowing the volume of EDTA used and the molarity of the EDTA solution, you can calculate the amount of CaO and MgO present in the cement sample.
Adding water to a vinegar sample prior to titration doesn't affect the calculated molarity because the number of moles of acetic acid present remains the same, regardless of the dilution. The amount of acetic acid reacting with the titrant in the titration is proportional to its initial concentration, not the volume of the solution.
What is the molarity of an HCl solution if 43.6 mL of a 0.125 M KOH solution are needed to titrate a 25.0 mL sample of the acid according to the equation below?
The normality of HCl can be calculated using the equation: Normality (HCl) * Volume (HCl) = Normality (NaOH) * Volume (NaOH). Solving for the normality of HCl gives 6.0N. The molarity of the HCl solution can be calculated using the formula: Molarity = Normality / n-factor. Assuming the n-factor for HCl is 1, the molarity of the HCl solution would be 6.0 M.
To find the molarity of the BaCl2 solution, first calculate the moles of Na2SO4 in the sample using its molar mass. Then, use the balanced chemical equation of the precipitation reaction to determine the moles of BaCl2 needed to react with the moles of Na2SO4. Finally, divide the moles of BaCl2 by the volume of the solution in liters (57.0 mL = 0.057 L) to find the molarity.
1.3g
Given that the volume ratio is 2:3 (48.0 mL: 25.0 mL), the molarity of the solution is also in the same ratio. Therefore, the molarity of the solution is (0.220 M * 3/2) = 0.330 M.
Molarity = moles of solute / liters of solution. First, calculate the moles of NaOH using its molar mass. Then, divide the moles by the final volume in liters (3.00 L) to find the molarity.
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
The molarity is 6.
Molarity is a measure of the concentration of a solution, representing the number of moles of solute per liter of solution. In volumetric analysis, it is important for accurately measuring the volume of solutions to determine the concentration of a solute using techniques such as titration. By knowing the molarity of a solution and the volume used in the analysis, you can calculate the amount of substance present in the sample being tested.
The molarity of acetone in water will depend on the concentration of acetone added to the water. Molarity is calculated as moles of solute divided by liters of solution. You would need to know the amount of acetone added to determine the molarity.
first measure the volume of the sample solution needed to change the blue color of the DCPIP solution into colourless. then, weigh the mass of the sample solution. finally calculate the concentration by using the formula: volume required t change the color of DCPIP solution (dm) per mass of the sample solution (g)
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).