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What is the molarity of 500 ml of a solution containing g AgNO3?
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What is the molarity a 500.0 ml solution containing 0.75 moles of solute?
The molarity of the solution is calculated using the formula: Molarity (M) = moles of solute / liters of solution. In this case, there are 0.75 moles of solute in 0.5 liters of solution (since 500 ml is equivalent to 0.5 L), so the molarity is 1.5 M.
What is the molarity of a solution that is made using 1.2 moles of a substance in 500mL?
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
What is the molarity of the resulting solution obtained by mixing 2.5liter of 0.5M urea solution and 500 ml of 2M urea solution?
To find the molarity of the resulting solution, we need to calculate the total moles of urea in both solutions and then find the total volume of the mixed solutions. Next, we divide the total moles of urea by the total volume in liters to get the molarity. After performing these calculations, the molarity of the resulting solution would be around 0.67M.
What is the resulting molarity when 100.00mL of a 0.125 M NaOH solutions is diluted to 500mL?
The moles of NaOH in the original solution is 0.125 M x 0.100 L = 0.0125 moles. When diluted to 500 mL, the new molarity will be 0.0125 moles / 0.500 L = 0.025 M.
Which is none concentrated solution containing 5 grams of salt and 10 grams of water or a solution containing 18 grams of salt and 90 grams of water?
The more concentrated solution is the one containing 18 grams of salt and 90 grams of water. This is because the concentration of the solute (salt) is higher in this solution compared to the solution containing 5 grams of salt and 10 grams of water.
What is the molarity of a solution that has 2.5 moles of solute dissolved in 500 mililiter of solution?
The molarity of the solution is calculated using the formula: Molarity (M) = moles of solute / liters of solution. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, plug in the values: M = 2.5 moles / 0.5 L = 5 M. Hence, the molarity of the solution is 5 M.
What is the molarity of a solution that contains 31.0 grams of HCl in 500cm3 of solution?
To calculate the molarity of the solution, first convert the mass of HCl to moles using its molar mass. Then, divide the number of moles by the volume of the solution in liters (500 cm3 = 0.5 L) to get the molarity.
What is molarity of solution containing 115g ethanol in 500 cc of solution?
5.0M Molarity is moles of solute/liters of solution. The molar mass of ethanol is 46.07 g/mol, so 115g of ethanol is 2.5 moles of ethanol. 500cc is the same as 0.5L. So 2.5 mol/0.5L = 5.0M
What is the molarity a 500.0 ml solution containing 0.75 moles of solute?
The molarity of the solution is calculated using the formula: Molarity (M) = moles of solute / liters of solution. In this case, there are 0.75 moles of solute in 0.5 liters of solution (since 500 ml is equivalent to 0.5 L), so the molarity is 1.5 M.
you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
What is the molarity of a solution that is made using 1.2 moles of a substance in 500mL?
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
What is the molarity of a solution containing 8 grams in 500 mL of solution?
The first step is to calculate the number of moles of the solute (8 g) using its molar mass. Next, divide the number of moles by the volume of the solution in liters (0.5 L) to find the molarity. In this case, the molarity would be determined to be 0.32 M.
What is the molarity of a solution in which 51 grams of aluminum oxide Al2O3 is dissolved in 500 mL of solution?
To find the molarity, you first need to calculate the number of moles of Al2O3. The molar mass of Al2O3 is 101.96 g/mol. Since you have 51 grams, that would be 0.5 moles. Next, convert the volume from mL to liters (500 mL = 0.5 L) and then divide the moles by the volume to get the molarity, which is 1.0 M.
What is the molarity of chloride ion in 100 ml of a 500 M barium chloride solution?
To find the molarity of chloride ion, you need to consider that one mole of barium chloride (BaCl2) will dissociate into two moles of chloride ions (Cl-). Therefore, the molarity of chloride ions in the solution will be twice the molarity of the barium chloride solution. In this case, the molarity of chloride ions would be 1000 M in the 500 M barium chloride solution.
What is the molarity of a solution containing 3.50 grams of NaCl in 500 mL of solution?
The molar mass of NaCl is about 58.44 g/mol. First, convert the mass of NaCl to moles: 3.50 g / 58.44 g/mol = 0.06 mol. Then, calculate the molarity by dividing the moles of solute by the volume of solution in liters: 0.06 mol / 0.5 L = 0.12 M.
What is the molarity of a solution containing 23G of nacl in 500 ml solution?
To find the molarity, first calculate the number of moles of NaCl. The molar mass of NaCl is 58.44 g/mol. So, 23 g / 58.44 g/mol = 0.39 mol. Then, divide the moles by the volume in liters: 0.39 mol / 0.5 L = 0.78 M. Therefore, the molarity of the solution is 0.78 M.
How many moles of sulfuric acid are in 500 mL of 0.324 M sulfuric acid solution?
To find the number of moles of sulfuric acid in the solution, multiply the volume of the solution (in liters) by the molarity. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, multiply 0.5 L by 0.324 mol/L to get 0.162 moles of sulfuric acid in 500 mL of the 0.324 M solution.
