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Li Molar Mass = 7g x 2 = 14g

CO3 Molar Mass = 60g

14+60=74

64g CO3 / 74g Li2CO3 = .81 = 81%

Its 81 percent. I wrote all the math up there for you. I'm an AP chemistry student, I hope my work helps you understand how this works.

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13y ago
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2w ago

The molar mass of Li2CO3 is 73.89 g/mol. The molar mass of CO32- is 60.01 g/mol. Therefore, the mass percentage of carbonate in Li2CO3 is (60.01 / 73.89) * 100% = 81.14%.

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Q: What is the mass percentage of carbonate in Li2CO3?
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Related questions

What is the balanced equation of lithium carbonate?

The balanced equation for lithium carbonate is Li2CO3.


What ionic compound is Li2CO3?

Lithium carbonate is the ionic compound with the formula Li2CO3. It is composed of lithium ions (Li+) and carbonate ions (CO3^2-).


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The formula mass of lithium carbonate (Li2CO3) is calculated by adding the atomic masses of each element in the compound. The atomic mass of lithium (Li) is approximately 6.94 g/mol, carbon (C) is 12.01 g/mol, and oxygen (O) is 16.00 g/mol. Therefore, the formula mass of Li2CO3 is (26.94) + 12.01 + (316.00) = 73.89 g/mol.


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Red lithium carbonate (Li2Co3)


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Is Li2CO3 ionic or covalent?

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