The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
The balanced chemical equation for the reaction is: Mg(OH)2 + 2HCl -> MgCl2 + 2H2O. From the equation, 1 mole of Mg(OH)2 reacts with 2 moles of HCl to produce 1 mole of MgCl2 and 2 moles of H2O. Since the molar mass of MgCl2 is 95.21 g/mol, the number of moles of MgCl2 produced can be calculated. Then, multiply the moles of MgCl2 by its molar mass to find the grams produced.
1 Mole of magnesium = 24.305 grams The 24.305 comes from the periodic table of elements. Simply find Mg and the atomic mass (the biggest number) is the same if u have 1 mole of that. So 24.305 grams x 4 = 97.22 grams
To find the number of moles of magnesium, we first need to calculate the molar mass of magnesium, which is 24.305 g/mol. Next, we convert the mass of the strip to moles using the formula moles = mass/molar mass. Plugging in the values, the number of moles of magnesium in the strip is 0.00463 moles.
The molecular mass of magnesium in magnesium chloride is 24.305 grams/mol.
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
To find the number of moles in 444 grams of magnesium chloride, you first need to calculate the molar mass of magnesium chloride. The molar mass of MgCl2 is about 95.21 g/mol. Next, calculate the number of moles by dividing the given mass by the molar mass: 444 g / 95.21 g/mol ≈ 4.66 moles of magnesium chloride.
To determine the number of moles in 53.8 g of magnesium chloride, you first need to calculate the molar mass of MgCl2 which is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 53.8 g / 95.21 g/mol = 0.565 moles.
To calculate the molarity, you first need to find the moles of magnesium chloride using its molar mass. The molar mass of magnesium chloride is 95.21 g/mol. Next, use the formula Molarity = moles of solute / liters of solution to find the molarity. Convert 250 ml to liters (0.25 L) and then calculate the molarity.
To find the mass of 9.40 moles of magnesium chloride (MgCl2), you multiply the molar mass of MgCl2 by the number of moles. The molar mass of MgCl2 is approximately 95.21 g/mol. Therefore, the mass of 9.40 moles of MgCl2 would be 895.54 grams.
To find the number of formula units in 33.8g of magnesium chloride (MgCl2), you first need to calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles, which is 0.355 moles. Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of formula units.
To determine the number of formula units in 12.2g of magnesium chloride, you need to first calculate the molar mass of magnesium chloride (MgCl2). The molar mass of MgCl2 is 95.21 g/mol. Next, divide the given mass (12.2g) by the molar mass of MgCl2 to find the number of moles present. Finally, use Avogadro's number (6.022 x 10^23) to convert moles to formula units.
To determine the number of formula units in 2.5 grams of Magnesium Chloride, you first need to calculate the molar mass of the compound (MgCl2). Then, use this molar mass to convert the grams of Magnesium Chloride to moles. Finally, use Avogadro's number (6.022×10^23) to find the number of formula units in the given amount of Magnesium Chloride.
To calculate the mass of magnesium chloride formed, you first need to write the balanced chemical equation for the reaction between HCl and magnesium to form magnesium chloride. Then, calculate the molar mass of HCl and magnesium chloride. Next, determine the number of moles of HCl using its molar mass and the given mass, and use the stoichiometry from the balanced equation to find the number of moles of magnesium chloride formed. Finally, calculate the mass of magnesium chloride using its molar mass and the number of moles.
To determine the number of formula units in 32.2 g of magnesium chloride (MgCl2), you need to first calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles, and finally, use Avogadro's number (6.022 × 10^23) to convert moles to formula units.
The balanced chemical equation for the reaction is: Mg(OH)2 + 2HCl -> MgCl2 + 2H2O. From the equation, 1 mole of Mg(OH)2 reacts with 2 moles of HCl to produce 1 mole of MgCl2 and 2 moles of H2O. Since the molar mass of MgCl2 is 95.21 g/mol, the number of moles of MgCl2 produced can be calculated. Then, multiply the moles of MgCl2 by its molar mass to find the grams produced.