The balanced chemical equation for the reaction between sodium (Na) and chlorine gas (Cl2) to form sodium chloride (NaCl) is: 2Na + Cl2 -> 2NaCl This equation shows that two moles of sodium combine with one mole of chlorine gas to produce two moles of sodium chloride.
The balanced equation for the reaction between chlorine gas and sodium to form sodium chloride is 2Na + Cl2 → 2NaCl. This means that for every 2 moles of sodium (Na), one mole of chlorine gas (Cl2) reacts to form 2 moles of sodium chloride (NaCl).
To calculate the volume of chlorine gas produced, you need to know the molar mass of chlorine and use the ideal gas law equation. First, convert the mass of chlorine gas to moles using its molar mass. Then use the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is temperature. Finally, you can solve for V to find the volume in liters.
Cl2 is chlorine. Chlorine exists as a diatomic molecule.
The atomic mass of chlorine gas is approximately 35.5 grams per mole.
To find the number of moles of Cl2 in 7.1g of chlorine, you need to divide the mass of Cl2 by its molar mass. The molar mass of Cl2 is 70.9 g/mol. Therefore, 7.1g / 70.9 g/mol = 0.1 moles of Cl2.
To calculate the number of moles in 140 g of Cl2, divide the given mass by the molar mass of Cl2. Number of moles = Mass / Molar mass = 140 g / 70.9 g/mol = 1.97 moles. Therefore, there are 1.97 moles of chlorine gas in 140 g of Cl2.
4.005
To calculate the number of moles in 15g of chlorine gas, you need to use its molar mass. The molar mass of chlorine is approximately 35.5 g/mol. Divide the given mass by the molar mass to find the number of moles. For 15g of chlorine gas, you will have about 0.42 moles.
The molar mass of chlorine gas (Cl2) is 70.91 g/mol. To convert grams to moles, you divide the mass (84 g) by the molar mass (70.91 g/mol). So, 84 grams of chlorine gas is equal to approximately 1.18 moles.
To find the number of moles in 79.3g of Cl2, first determine the molar mass of Cl2 (35.5g/mol x 2 = 71g/mol). Next, divide the given mass by the molar mass to get the number of moles (79.3g / 71g/mol = 1.12 moles of Cl2).
To convert grams of a substance to moles, you need to use the molar mass. The molar mass of chlorine gas (Cl2) is approximately 70.9 g/mol. So, to convert 120g of chlorine gas to moles, you would divide 120g by 70.9 g/mol, giving you approximately 1.69 moles.
The balanced chemical equation for the reaction between chlorine gas and sodium is: 2Na + Cl2 -> 2NaCl Using the equation, we can see that 1 mole of chlorine gas (Cl2) reacts with 2 moles of sodium (2Na). To calculate the mass of chlorine gas needed to react with 92 grams of sodium, first convert 92 grams of sodium to moles, then use the mole ratio from the balanced equation to find the moles of chlorine gas needed. Finally, convert the moles of chlorine gas to grams.
To produce 1.5 moles of chloroform (CHCl3), you would need 3 moles of chlorine (Cl2) as the reaction is 1:1 between Cl2 and CHCl3. The molar mass of Cl2 is approximately 70.9 g/mol, so 3 moles of Cl2 would be 3 * 70.9 g. Therefore, you would need approximately 212.7 grams of Cl2.
There are approximately 1.97 moles of chlorine in 70g. This is calculated by dividing the mass of the sample by the molar mass of chlorine (approximately 35.5 g/mol).
First, calculate the moles of Cl2 with the given mass and molar mass (70.9 g/mol). Use the mole ratio between Cl2 and PCl5 (4:1) to find the moles of PCl5 produced. So, for 56.0g Cl2, 0.790 moles of PCl5 can be produced.
Since chlorine gas is a diatomic molecule (Cl2), one mole of chlorine gas contains two moles of chlorine atoms. Therefore, 6.00 moles of chlorine atoms would be equivalent to 3.00 moles of chlorine gas.