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To find the mass of 200 moles of NH3 (ammonia), you'll need to know the molar mass of NH3, which is approximately 17.03 g/mol. Multiply the molar mass by the number of moles to get the mass: 17.03 g/mol x 200 mol = 3406 g. Therefore, the mass of 200 moles of NH3 is 3406 grams.
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What mass of NH3 is produced when 1.20 mol of N2 react completely in the following equation N2 plus 3H2 2NH3?
N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3
How many gram of f2 are required to react with 3.50 moles of nh3?
The balanced chemical equation for the reaction between F2 and NH3 is: 3 F2 + 4 NH3 -> 6 HF + N2 From the equation, we can see that 3 moles of F2 react with 4 moles of NH3. To find the moles of F2 required to react with 3.50 moles of NH3, we can set up a proportion: 3 moles F2 / 4 moles NH3 = x moles F2 / 3.50 moles NH3 Solving for x, we find that 2.625 moles of F2 are required. To convert this to grams, we use the molar mass of F2 which is approximately 38.00 g/mol. 2.625 moles F2 x 38.00 g/mol = 99.75 grams of F2 required to react with 3.50 moles of NH3.
How many moles of NH3 can be produced from 2.37x10-4 moles of H2?
The balanced chemical equation for the reaction is: 3H2 + N2 -> 2NH3 From the equation, we can see that 3 moles of H2 are required to produce 2 moles of NH3. Therefore, the number of moles of NH3 that can be produced from 2.37x10-4 moles of H2 is 2.37x10-4 mol x (2 mol NH3 / 3 mol H2) = 1.58x10-4 moles of NH3.
How many moles of NH3 can be produced from the reaction of 75g of N2?
0,044 moles of NH3 can be produced.
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
Since the balanced chemical equation for the reaction is 4NH3 → 3N2, you can see that 4 moles of NH3 produce 3 moles of N2. This means that 5.0 moles of NH3 would produce 3.75 moles of N2.
What is can the mass NH3 made if they give you the gram?
To find the mass of NH3 produced, first calculate the number of moles of NH3 using the given mass and the molar mass of NH3. Then, use the relationship between moles and mass (mass = moles x molar mass) to find the mass of NH3.
How many moles of NH3 are present in 107.1g?
To find the number of moles of NH3 in 107.1g, divide the given mass by the molar mass of NH3. The molar mass of NH3 is 17.03 g/mol. ( \frac{107.1 , \text{g}}{17.03 , \text{g/mol}} ≈ 6.29 , \text{mol} ) of NH3 are present.
The formula for ammonia is NH3. The mass of 3 moles of ammonia would be grams.?
The molar mass of NH3 is 17.03 g/mol. To find the mass of 3 moles of NH3, you would multiply the molar mass by 3. Therefore, the mass of 3 moles of ammonia would be 51.09 grams.
How many moles of NH3 is in 23g of NH3?
Atomic mass of NH3 is 17.So there are 1.353mol.
How many moles are in 4.00g of NH3?
To find the number of moles in 4.00g of NH3, you first need to calculate the molar mass of NH3 (17.03 g/mol). Then, divide the given mass by the molar mass to get the number of moles. So, 4.00g / 17.03 g/mol = 0.235 moles of NH3.
How many moles are present in 1g of ammonia?
To calculate the number of moles in 1g of ammonia (NH3), you first need to determine the molar mass of ammonia. The molar mass of NH3 is approximately 17 g/mol. Then you can use the formula: number of moles = mass / molar mass. So for 1g of NH3, there would be approximately 0.059 moles present.
100 grams of ammonia equals how many moles?
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
Calculate mass in grams of 2.110 moles of NH3?
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
How many moles of hydrogen are needed to make 170000 g of ammonia?
To determine the number of moles of hydrogen needed to make 170000 g of ammonia (NH3), first calculate the molar mass of NH3 (17 g/mol). NH3 has 3 hydrogen atoms, so each mole of NH3 requires 3 moles of hydrogen. Therefore, divide the given mass of NH3 by its molar mass to find the moles of NH3, then multiply by 3 to get the moles of hydrogen needed.
What mass of NH3 is produced when 1.20 mol of N2 react completely in the following equation N2 plus 3H2 2NH3?
N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3
How many moles in 0.75 g of ammonia?
To find the number of moles in 0.75 g of ammonia (NH3), you first need to calculate the molar mass of ammonia (NH3) which is approximately 17 g/mol. Then divide the given mass (0.75 g) by the molar mass to get the number of moles. In this case, 0.75 g of ammonia is equivalent to about 0.044 moles.
How many moles are in 12 x 10.3 grams of ammonia NH3?
To find the number of moles in 12 x 10.3 grams of ammonia (NH3), you first need to calculate the molar mass of NH3 (17.03 g/mol). Then divide the given mass (12 x 10.3 g) by the molar mass to get the number of moles, which should be approximately 72 moles.
