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16 grams per mole. Methane is CH4. Look at the Periodic Table: Carbon is 12 grams/mole and Hydrogen is 1 gram/mole, so 1*12 + 4*1 = 16.
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What is the atomic mass in grams of 0.35 moles of CH4?
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
How many moles of methane are presentin 5.6L of the gas at stp?
0.25 moles
How many electron are present in 1.6g of methane?
First you must find the no. on moles in 1.6g of ch4. ie. ch4=C+h4=12+(1.008x4)=16.032 or 16 approx moles=1.6/16=0.1 No. of electrons=no. atoms ie. no of moles x 6.022x10^23 =0.1x 6.022x10^23 =>6.022 x 10^22(approx)
Description of 16.0 grams of methane?
16.0 grams of methane (CH4) is equivalent to about 0.92 moles of methane, since the molar mass of methane is approximately 16.04 g/mol. In terms of molecules, this would be approximately 5.53 x 10^22 molecules of methane.
How many molecules are in 4n of methane?
If you think to 4 moles of methane the number is 24,088563428.10e+23.
How many moles of methane are there in 8.02 g of methane?
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
How many moles are in 0.289 g of methane?
To find the number of moles in 0.289 g of methane, first calculate the molar mass of methane (CH4), which is approximately 16 g/mol. Next, divide the given mass (0.289 g) by the molar mass to obtain the number of moles. Therefore, 0.289 g of methane is equivalent to 0.289 g / 16 g/mol ≈ 0.018 moles of methane.
The formula for methane is CH4. Four moles of methane would have a mass of how many grams?
To calculate the mass of four moles of methane (CH4), we first need to determine the molar mass of methane. The molar mass of CH4 is the sum of the atomic masses of carbon (12.01 g/mol) and hydrogen (1.008 g/mol) multiplied by the number of atoms in the compound. Therefore, the molar mass of CH4 is 12.01 g/mol + 4(1.008 g/mol) = 16.04 g/mol. To find the mass of four moles of methane, we multiply the molar mass by the number of moles: 16.04 g/mol x 4 mol = 64.16 grams. Therefore, four moles of methane would have a mass of 64.16 grams.
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
The balanced chemical equation for the combustion of methane is: CH4 + 2O2 -> CO2 + 2H2O From the equation, 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane is 16 g/mol, so 100.0 grams of methane is 100.0/16 = 6.25 moles. Therefore, 6.25 moles of carbon dioxide will be produced.
How many grams Four moles of methane would have a mass of how many grams?
2344222.445
The formula for methane is CH4 Four moles of methanes would have a mass of?
The molar mass of methane (CH4) is 16 g/mol. Therefore, four moles of methane would have a mass of 64 grams.
How many moles of hydrogen are present in 3 moles of methane?
There are 6 moles of hydrogen atoms in 3 moles of methane since the chemical formula for methane (CH4) contains four hydrogen atoms for every one carbon atom.
How many moles of water are associated with each mole of methane hydrate if a sample has 160cm3 methane and 1000g of water ar room temperature and pressure?
For each mole of methane hydrate, there are 5.75 moles of water associated with it. In this case, since you have 160 cm³ of methane and 1000g of water, we first convert 160 cm³ of methane to moles, which is 5.62 moles. Then we calculate the moles of water based on the ratio 1:5.75 for methane to water in methane hydrate, which gives us approximately 32.3 moles of water associated with the 5.62 moles of methane.
If in the previous problem only 25.9 grams of water vapor were formed how much methane actually reacted with oxygen?
The equation for the reaction between methane (CH4) and oxygen is: CH4 + 2O2 → CO2 + 2H2O From the previous information, if 25.9 grams of water vapor were formed, this corresponds to 25.9 grams ÷ 18.0 g/mol = 1.44 moles of water. This means 0.72 moles of methane reacted. If the molar mass of methane is 16.0 g/mol, then 0.72 moles of methane corresponds to 0.72 moles × 16.0 g/mol = 11.52 grams of methane reacted with oxygen.
What is the atomic mass in grams of 0.35 moles of CH4?
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
What mass of water is produced from the complete combustion of 2.50x10-3 of methane?
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This shows that for every mole of methane that is combusted, 2 moles of water are produced. Calculate the amount of water produced by converting the given moles of methane to moles of water, and then to mass using the molar mass of water.
How many moles of carbon dioxide are formed from 14 moles of methane?
When methane (CH4) is burned in excess oxygen, it forms carbon dioxide (CO2) and water (H2O). The balanced chemical equation is: CH4 + 2O2 --> CO2 + 2H2O From the equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. Therefore, 14 moles of methane will produce 14 moles of carbon dioxide.
