16 grams per mole. Methane is CH4. Look at the Periodic Table: Carbon is 12 grams/mole and Hydrogen is 1 gram/mole, so 1*12 + 4*1 = 16.
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
0.25 moles
First you must find the no. on moles in 1.6g of ch4. ie. ch4=C+h4=12+(1.008x4)=16.032 or 16 approx moles=1.6/16=0.1 No. of electrons=no. atoms ie. no of moles x 6.022x10^23 =0.1x 6.022x10^23 =>6.022 x 10^22(approx)
16.0 grams of methane (CH4) is equivalent to about 0.92 moles of methane, since the molar mass of methane is approximately 16.04 g/mol. In terms of molecules, this would be approximately 5.53 x 10^22 molecules of methane.
If you think to 4 moles of methane the number is 24,088563428.10e+23.
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
To find the number of moles in 0.289 g of methane, first calculate the molar mass of methane (CH4), which is approximately 16 g/mol. Next, divide the given mass (0.289 g) by the molar mass to obtain the number of moles. Therefore, 0.289 g of methane is equivalent to 0.289 g / 16 g/mol โ 0.018 moles of methane.
Taking carbon @ 12.01 g/mol & hydrogen @ 1.01 g/ mol methane has 1 carbon & 4 hydrogen, so it is:12.01g + 4(1.01g) = 16.05g per mole.For 4 moles: 4 x 16.05 g = 64.20 g
The balanced chemical equation for the combustion of methane is: CH4 + 2O2 -> CO2 + 2H2O From the equation, 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane is 16 g/mol, so 100.0 grams of methane is 100.0/16 = 6.25 moles. Therefore, 6.25 moles of carbon dioxide will be produced.
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The molar mass of methane (CH4) is 16 g/mol. Therefore, four moles of methane would have a mass of 64 grams.
There are 6 moles of hydrogen atoms in 3 moles of methane since the chemical formula for methane (CH4) contains four hydrogen atoms for every one carbon atom.
For each mole of methane hydrate, there are 5.75 moles of water associated with it. In this case, since you have 160 cmยณ of methane and 1000g of water, we first convert 160 cmยณ of methane to moles, which is 5.62 moles. Then we calculate the moles of water based on the ratio 1:5.75 for methane to water in methane hydrate, which gives us approximately 32.3 moles of water associated with the 5.62 moles of methane.
The equation for the reaction between methane (CH4) and oxygen is: CH4 + 2O2 โ CO2 + 2H2O From the previous information, if 25.9 grams of water vapor were formed, this corresponds to 25.9 grams รท 18.0 g/mol = 1.44 moles of water. This means 0.72 moles of methane reacted. If the molar mass of methane is 16.0 g/mol, then 0.72 moles of methane corresponds to 0.72 moles ร 16.0 g/mol = 11.52 grams of methane reacted with oxygen.
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This shows that for every mole of methane that is combusted, 2 moles of water are produced. Calculate the amount of water produced by converting the given moles of methane to moles of water, and then to mass using the molar mass of water.
When methane (CH4) is burned in excess oxygen, it forms carbon dioxide (CO2) and water (H2O). The balanced chemical equation is: CH4 + 2O2 --> CO2 + 2H2O From the equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. Therefore, 14 moles of methane will produce 14 moles of carbon dioxide.