I believe it is CO2 (g) <-> CO2 (aq)
It uses a double arrow that I can't accurately write here to describe equilibrium.
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You're supposed to actually draw the double arrow like that.
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The equilibrium equation for the reaction between Na2CO3 and NaHCO3 is:
Na2CO3 + H2O ⇌ 2NaOH + CO2
This reaction occurs when NaHCO3 (sodium bicarbonate) reacts with water to form Na2CO3 (sodium carbonate), NaOH (sodium hydroxide), and CO2 (carbon dioxide).
The equilibrium equation for Na2CO3 NaHCO3 is CO32- + H+ <---> HCO3- pH = pKa + log [CO32-] / [HCO3-].
Na2CO3 (sodium carbonate) plus H2O (water) and CO2 (carbon dioxide) will undergo a chemical reaction to form sodium bicarbonate (NaHCO3). The balanced chemical equation for this reaction is: Na2CO3 + H2O + CO2 -> 2 NaHCO3.
The symbol equation for the decomposition of sodium hydrogen carbonate is: 2 NaHCO3 → Na2CO3 + H2O + CO2
NaHCO3 (sodium bicarbonate) is more acidic than Na2CO3 (sodium carbonate) because NaHCO3 can release more hydrogen ions when it dissolves in water due to the presence of the hydrogen carbonate ion. Na2CO3 contains the carbonate ion, which is a weaker base compared to the bicarbonate ion in NaHCO3.
The balanced chemical equation for the breakdown of sodium bicarbonate (NaHCO3) is: 2 NaHCO3 -> Na2CO3 + CO2 + H2O From this equation, it can be seen that one mole of NaHCO3 produces one mole of H2O. The molar mass of NaHCO3 is 84 g/mol. Therefore, 168 g of NaHCO3 will produce 84 g of H2O.
The neutralization equation for the reaction between acetyl salicylic acid (HC5H7O4CO2) and sodium bicarbonate (NaHCO3) is: HC5H7O5CO2 + NaHCO3 -> NaC9H7O4 + H2O + CO2.