RbI + AgNO3 ---> RbNO3 + AgI
It is displacement reaction. Rubidium is an alkali metal hence it is highly reactive and easily displaces silver from silver nitrate solution.
The chemical equation for Strontium Iodide is SrI2, which represents the compound formed by the elements strontium (Sr) and iodine (I) combining in a 1:2 ratio.
When silver nitrate and strontium iodide react, a double displacement reaction occurs. Silver iodide and strontium nitrate are formed as products. Silver iodide is a yellow precipitate while strontium nitrate remains in solution.
The formula for mercury iodide is HgI2. In chemical reactions, mercury iodide can decompose into its elements: HgI2(s) -> Hg(l) + I2(g).
The molecular formula for silver iodide is AgI.Silver iodide is an inorganic, yellow compound which is used in many things, from silver-based photography to antiseptic.
The reaction is:Ag+ + (NO3)- + K + I- = AgI(s) + (NO3)- + K
When sodium iodide reacts with silver nitrate, they form sodium nitrate and silver iodide. The balanced chemical equation for this reaction is: 2NaI + AgNO3 -> 2NaNO3 + AgI
Word equation: Lead(II) nitrate + Sodium iodide -> Lead(II) iodide + Sodium nitrate. Balanced chemical equation: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3.
The chemical name of the compound RbI is rubidium iodide.
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium iodide (KI) is: Ag+ + I- → AgI(s). This equation represents the formation of silver iodide as a solid precipitate.
The chemical formula of rubidium chloride is RbCl.
The chemical reaction between lead nitrate and potassium iodide produces lead iodide and potassium nitrate. The balanced chemical equation is: 2Pb(NO3)2 + 2KI -> 2PbI2 + 2KNO3
The chemical formula for lead nitrate is Pb(NO3)2 and for potassium iodide it is KI.
The balanced chemical equation for silver nitrate (AgNO3) plus calcium iodide (CaI2) is: 2AgNO3 + CaI2 -> 2AgI + Ca(NO3)2
The chemical equation for the reaction between lead nitrate (Pb(NO3)2) and potassium iodide (KI) to form lead iodide (PbI2) and potassium nitrate (KNO3) is: Pb(NO3)2 + 2KI → 2KNO3 + PbI2
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
When iodide is mixed with silver nitrate, a yellow precipitate of silver iodide is formed due to a double displacement reaction. This reaction can be represented by the chemical equation: 2AgNO3 + 2KI → 2AgI + 2KNO3.
When rubidium reacts with iodine, it will form rubidium iodide (RbI), a salt composed of rubidium cations (Rb+) and iodide anions (I-).