The chemical equation for Strontium Iodide is SrI2, which represents the compound formed by the elements strontium (Sr) and iodine (I) combining in a 1:2 ratio.
When silver nitrate and strontium iodide react, a double displacement reaction occurs. Silver iodide and strontium nitrate are formed as products. Silver iodide is a yellow precipitate while strontium nitrate remains in solution.
The formula for mercury iodide is HgI2. In chemical reactions, mercury iodide can decompose into its elements: HgI2(s) -> Hg(l) + I2(g).
The molecular formula for silver iodide is AgI.Silver iodide is an inorganic, yellow compound which is used in many things, from silver-based photography to antiseptic.
The reaction is:Ag+ + (NO3)- + K + I- = AgI(s) + (NO3)- + K
When sodium iodide reacts with silver nitrate, they form sodium nitrate and silver iodide. The balanced chemical equation for this reaction is: 2NaI + AgNO3 -> 2NaNO3 + AgI
The chemical name of the compound RbI is rubidium iodide.
Word equation: Lead(II) nitrate + Sodium iodide -> Lead(II) iodide + Sodium nitrate. Balanced chemical equation: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3.
The ionic equation for the reaction between silver nitrate (AgNO3) and potassium iodide (KI) is: Ag+ + I- β AgI(s). This equation represents the formation of silver iodide as a solid precipitate.
The chemical formula of rubidium chloride is RbCl.
The chemical reaction between lead nitrate and potassium iodide produces lead iodide and potassium nitrate. The balanced chemical equation is: 2Pb(NO3)2 + 2KI -> 2PbI2 + 2KNO3
The chemical formula for lead nitrate is Pb(NO3)2 and for potassium iodide it is KI.
The balanced chemical equation for silver nitrate (AgNO3) plus calcium iodide (CaI2) is: 2AgNO3 + CaI2 -> 2AgI + Ca(NO3)2
The chemical equation for the reaction between lead nitrate (Pb(NO3)2) and potassium iodide (KI) to form lead iodide (PbI2) and potassium nitrate (KNO3) is: Pb(NO3)2 + 2KI β 2KNO3 + PbI2
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
When iodide is mixed with silver nitrate, a yellow precipitate of silver iodide is formed due to a double displacement reaction. This reaction can be represented by the chemical equation: 2AgNO3 + 2KI β 2AgI + 2KNO3.
When rubidium reacts with iodine, it will form rubidium iodide (RbI), a salt composed of rubidium cations (Rb+) and iodide anions (I-).